Given:
The expression is

To find:
The product of prime polynomials which is equivalent to the given expression.
Solution:
We have,

Taking out the common factors, we get

It can be written as

![[\because a^3-b^3=(a-b)(a^2+ab+b^2)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E3-b%5E3%3D%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29%5D)


Therefore, the correct option is B.
Answer:
Step-by-step explanation:
You know that ...
- cos(θ)² = 1 - sin(θ)²
- tan(θ) = sin(θ)/cos(θ)
- cosine is negative in the third quadrant (where π < θ < 3π/2)
Using what you know about the relationships of these trig functions, you can find ...
cos(θ)² = 1 - ((-√3)/2)² = 1 - 3/4 = 1/4
cos(θ) = -1/2 . . . . . negative square root of 1/4
__
tan(θ) = sin(θ)/cos(θ) = ((-√3)/2)/(-1/2)
tan(θ) = √3
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