Question

At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent inecrease of water in the tank

Answer 1

Question:

At noon a tank contains 6 cm of water after several hours it contains 3 cm of water what is the percent decrease of water in the tank

Answer:

The percent Decrease of water in the tank  is 50%

Step-by-step explanation:

Given:

Initial amount of water in the tank at the noon = 6 cm

amount of water remained in water after several hours = 3 cm

To Find:

The percent decrease =?

Solution:

The percent decrease in the tank

=>$\frac{\text {water present after some hours }}{\text {initial water contained in the tank }} \times 100$

Substituting the values

=>$\frac{3}{6} \times 100$

=>$\frac{1}{2} \times 100$

=>$\frac{100}{2}$

=> 50