The GCF of 15 and 27 is _____.
2 answers:
You might be interested in
1331 x³ = 216
x³ = 216/1331
x =![\sqrt[3]{ \frac{216}{1331} } = \frac{6}{11}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B216%7D%7B1331%7D%20%7D%20%3D%20%20%5Cfrac%7B6%7D%7B11%7D%20)
Thank you.
x³ = 216/1331
x =
Thank you.
Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒
Equation [2] ⇒
We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;
and 
, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either or the subject:
Then we substitute into Equation [2]
Now we know the value of which is , substitute this value into we have 
Answer:
Numbers of books = 13
Numbers of CDs = 7
We can set up two equations:
Equation [1] ⇒
Equation [2] ⇒
We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;
First, rearrange Equation [1] to make either
Then we substitute
Now we know the value of
Answer:
Numbers of books = 13
Numbers of CDs = 7