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nata0808 [166]
3 years ago
8

What’s 30x8+5 divided by 8% =

Mathematics
1 answer:
mr_godi [17]3 years ago
8 0

Answer:

302.5

Step-by-step explanation:

30 x 8

5/8

I hope this helps I'm like 90 percent sure this is right. There is no other answer I could think of so I hope Hope helpa

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Which expression uses the greatest common factor and the distributive property to rewrite the sum 7 + 75
Lady_Fox [76]

Answer:

75 + 45 = 15(3 + 5)

Step-by-step explanation:

Given

75 + 45 <em>-- Corrected</em>

Required

Use the GCF to write it as a distributive property

First, we find the GCF of 75 and 45

45 = 3 * 3 * 5

75 = 3 * 5 * 5

The common factor is:

GCF = 3 * 5

GCF = 15

So, 75 + 45 becomes

75 + 45 = 15 * 3 + 15 * 5

Factorize

75 + 45 = 15(3 + 5)

<em>Hence, the sum has been rewritten as </em>15(3 + 5)<em></em>

5 0
3 years ago
Identify PR rounded to the nearest tenth. Please help asap!!
kicyunya [14]

Trigonometric Functions:

S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}

Sine\frac{Opposite}{Hypotenuse} Cos\frac{Adjacent}{Hypotenuse} Tan\frac{Opposite}{Adjacent}

You have the angle and the adjacent. You need to find the hypotenuse (PR). Therefore, you use cos.

Cos(26)=\frac{13}{H}

Rearrange the formula to find H (PR):

H = \frac{13}{Cos(26)}

14.463 ~ 14.5

<h2>14.5°</h2>
5 0
3 years ago
Formulas A=bh/2 A=bh and I have 6in 4in 6in 10in and I have to find the area
Naddik [55]

Answer:

Lots of "ifs" here.

A=bh/2 is the formula for the area of a triangle.

A=bh is the formula for the area of a rectangle or a parallelogram.

If the 6 & 4 area the base & height of a rectangle, then (6)(4) = 24 in^2

If the 6 & 10 are the base and height of a triangle, then 1/2(6)(10) = 30 in^2

Step-by-step explanation:

6 0
3 years ago
The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $5.50 and
Pani-rosa [81]

Answer:

i dont know

Step-by-step explanation:

:0

4 0
3 years ago
Read 2 more answers
Question<br> Find the distance between the points (-5, 8) and (-3,0).
Temka [501]

To calculate the distance between two points we use this formula:

\boxed{ \boxed{{d \:  =   \:  \sqrt{(x_2 \:  -  \: x_1)^{2} \:  +  \: (y_2 \:  -  \: y_1)^{2} } }}}

<h3>______________________</h3>

<h3>We organize the values:</h3>

  • x₁ = -5
  • x₂ = -3
  • y₁ = 8
  • y₂ = 0

______________________

We apply the values already obtained to the formula to get the distance:

d \:  =   \:  \sqrt{( - 3 \:  -  \:( - 5))^{2} \:  +  \: (0 \:  -  \: 8)^{2} }

d \:  =   \:  \sqrt{( - 3 \:  -  \: ( - 5))^{2} \:  +  \: ( - 8)^{2} }

d \:  =  \:  \sqrt{( - 3 \:  +  \: 5) ^{2}  \:  +  \: 64 }

d \:  =  \:  \sqrt{ {2}^{2} \:  +  \: 64 }

d \:  =  \:  \sqrt{4 \:  +  \: 64}

d \:  =  \:  \sqrt{68}

d \:  = \boxed{ \bold{  \: 2 \sqrt{17}  \:   units}}

<h2>Answer: </h2>

\huge{\boxed{ \bold{2 \sqrt{17} \: units }}}

<h3><em><u>MissSpanish</u></em></h3>
7 0
2 years ago
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