What is group A called?<br> What is group B called ?

1. Which of the following represent distributive property?

pshichka [43]

I think the answer is B hope this helps.

3 0

3 years ago

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Enter the equation of the line in the form y=mx where m is the slope.Immersive Reader

kari74 [83]

Answer:

y = 1/2x

Step-by-step explanation:

The slope is the rise (up) over run (left or right depending on if the number is negative) between points. So the next point on the graph is up 5 and over 10. this simplified is 1/2. Then you put this into y=mx which is y=1/2x

4 0

3 years ago

How to solve 4(a-2)=3(a+4)

Blababa [14]

Use the distributive property.
4a - 8 = 3a + 12
Arrange the like terms.
4a - 3a = 12 + 8
a = 20
That is the answer. <span>☺️</span>✌️

5 0

4 years ago

A data set with a mean of 34 and a standard deviation of 2.5 is normally distributed

tresset_1 [31]

Answer:

a) $z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

b) $P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

c) $z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

Step-by-step explanation:

For this case we have a random variable with the following parameters:

$X \sim N(\mu = 34, \sigma=2.5)$

From the empirical rule we know that within one deviation from the mean we have 68% of the values, within two deviations we have 95% and within 3 deviations we have 99.7% of the data.

We want to find the following probability:

$P(34 < X$

We can find the number of deviation from the mean with the z score formula:

$z= \frac{X -\mu}{\sigma}$

And replacing we got

$z= \frac{34-34}{2.5}= 0$

$z= \frac{39-34}{2.5}= 2$

And we want the probability from 0 to two deviations above the mean and we got 95/2 = 47.5 %

For the second case:

$P(X$

$z= \frac{31.5-34}{2.5}= -1$

So one deviation below the mean we have: (100-68)/2 = 16%

For the third case:

$P(29 < X$

And replacing we got:

$z= \frac{29-34}{2.5}= -2$

$z= \frac{36.5-34}{2.5}= 1$

For this case below 2 deviation from the mean we have 2.5% and above 1 deviation from the mean we got 16% and then the percentage between -2 and 1 deviation above the mean we got: (100-16-2.5)% = 81.5%

7 0

3 years ago

Help me wick show you work

expeople1 [14]

3 to 9 clouds are smiley faces Explaintion- hope it’s right

3 0

3 years ago

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What is group A called? What is group B called ?