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2 years ago

15y + v4-8 What is the degree

Mathematics

1 answer:

natulia [17]2 years ago

6 0

Answer: The degree of 15y+v4-8 is 1

Step-by-step explanation: Hope this helps in your studies!

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Can someone help me

ryzh [129]

Answer:

Answer a: mST=20

Answer b: mST=48

Step-by-step explanation:

Problem a:

3a-5=2a+50

a=55

2(55)+50=160

180-160=20

Problem b:

180=4c-12

192=4c

48=c

7 0

3 years ago

Which two values are located at the same point on a number line? 1/2 and 2 , 2/2 2 , 2/1 2 , 2/1 and 1

grandymaker [24]

Answer: $\frac{2}{2},1\ \text{and}\ \frac{2}{2},1$

Step-by-step explanation:

$\Rightarrow \dfrac{2}{2}\ \text{is equivalent to 1}$

$\text{So, }\ \dfrac{2}{2},2\ \text{is equivalent to 1,2}$

$\text{Similarly, }\ \dfrac{2}{1},1\ \text{represents 2,1 or 1,2}$

$\text{So,}\ \frac{2}{2},1\ \text{and}\ \frac{2}{2},1\ \text{are represents same on number line.}$

8 0

2 years ago

The cost of a regular price ticket to a Saint Louis Cardinal baseball game was $60. During the World

dezoksy [38]

1/5 of $60 is $12.

Therefore, 2/5 of $60 is $24.

If the price of tickets increased by 2/5 during the World Series, then during the World Series a ticket would've cost $60+$24=$84.

6 0

3 years ago

Read 2 more answers

Can anybody show me how to do this half angle identity problem STEP BY STEP? I always seem to be missing something

klio [65]

Answer: $\bold{-\dfrac{7\sqrt2}{10}}$

<u>Step-by-step explanation:</u>

It is given that θ is between 270° and 360°, which means that θ is located in Quadrant IV ⇒ (x > 0, y < 0). Furthermore, the half-angle will be between 135° and 180°, which means the half-angle is in Quadrant II ⇒ $cos\ \dfrac{\theta}{2}$

It is given that sin θ = $-\dfrac{7}{25}$ ⇒ y = -7 & hyp = 25

Use Pythagorean Theorem to find "x":

x² + y² = hyp²

x² + (-7)² = 25²

x² + 49 = 625

x² = 576

x = 24

Use the "x" and "hyp" values to find cos θ:

$cos\ \theta=\dfrac{x}{hyp}=\dfrac{24}{25}$

Lastly, input cos θ into the half angle formula:

$cos\bigg(\dfrac{\theta}{2}\bigg)=\pm \sqrt{\dfrac{1+cos\ \theta}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{1+\dfrac{24}{25}}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{\dfrac{25}{25}+\dfrac{24}{25}}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{\dfrac{49}{25}}{2}}\\\\\\.\qquad \quad =\pm \sqrt{\dfrac{49}{50}}\\\\\\.\qquad \quad =\pm \dfrac{7}{5\sqrt2}}\\\\\\.\qquad \quad =\pm \dfrac{7}{5\sqrt2}}\bigg(\dfrac{\sqrt2}{\sqrt2}\bigg)\\\\\\.\qquad \quad =\pm \dfrac{7\sqrt2}{10}$

Reminder: We previously determined that the half-angle will be negative.

6 0

2 years ago

Assume that ∠A is an acute angle. If sin A = 0.994, use a calculator to find the measure of ∠A to two decimal places. The mea

Sedbober [7]

Basically, you are looking for the ARC SINE of .994 which is
83.72 Degrees
You could also use an online calculator:
http://www.1728.org/trigcalc.htm

8 0

2 years ago