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Solnce55 [7]
2 years ago
9

15y + v4-8 What is the degree

Mathematics
1 answer:
natulia [17]2 years ago
6 0

Answer: The degree of 15y+v4-8 is 1

Step-by-step explanation: Hope this helps in your studies!

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Please help I’ll give brainliest
Fed [463]

Answer:

$48

Step-by-step explanation:

$160 * 0.05 = $8

$8 * 6 = $48

Hope this helps

5 0
2 years ago
Read 2 more answers
The indicated function y1(x is a solution of the given differential equation. use reduction of order or formula (5 in section 4.
Taya2010 [7]
Given a solution y_1(x)=\ln x, we can attempt to find a solution of the form y_2(x)=v(x)y_1(x). We have derivatives

y_2=v\ln x
{y_2}'=v'\ln x+\dfrac vx
{y_2}''=v''\ln x+\dfrac{v'}x+\dfrac{v'x-v}{x^2}=v''\ln x+\dfrac{2v'}x-\dfrac v{x^2}

Substituting into the ODE, we get

v''x\ln x+2v'-\dfrac vx+v'\ln x+\dfrac vx=0
v''x\ln x+(2+\ln x)v'=0

Setting w=v', we end up with the linear ODE

w'x\ln x+(2+\ln x)w=0

Multiplying both sides by \ln x, we have

w' x(\ln x)^2+(2\ln x+(\ln x)^2)w=0

and noting that

\dfrac{\mathrm d}{\mathrm dx}\left[x(\ln x)^2\right]=(\ln x)^2+\dfrac{2x\ln x}x=(\ln x)^2+2\ln x

we can write the ODE as

\dfrac{\mathrm d}{\mathrm dx}\left[wx(\ln x)^2\right]=0

Integrating both sides with respect to x, we get

wx(\ln x)^2=C_1
w=\dfrac{C_1}{x(\ln x)^2}

Now solve for v:

v'=\dfrac{C_1}{x(\ln x)^2}
v=-\dfrac{C_1}{\ln x}+C_2

So you have

y_2=v\ln x=-C_1+C_2\ln x

and given that y_1=\ln x, the second term in y_2 is already taken into account in the solution set, which means that y_2=1, i.e. any constant solution is in the solution set.
4 0
2 years ago
A submarine began a 120 feet below sea level and ascended at a rate of 13 feet per minute. What was the depth of the submarine a
Triss [41]

The submarine would be 900 below the ocean surface after 12 minutes assuming it started its descent at the surface of the ocean.

7 0
3 years ago
What is the volume of a box with width 2 2/3 inches, length 3 1/3 , inches, and height 2 1/3. inches?​
g100num [7]

Answer:

It is 20.74 and the fraction way it is 20 20/27

6 0
2 years ago
How do you graph this <br> y-2x=0<br> y=4x+3
Svetlanka [38]

Answer:

Step-by-step explanation:

those are 2 lines, and to graph them find 2 points for each to draw a line trough them

line 1

y-2x=0 so y=2x

pick any value for x

(x=1, y=2*1=2), (x=3, y=2*3=6)

Draw a line trough points (1,2) and (3,6)

line 2

y=4x+3

(x=1, y=4*1+3=7), (x= -1, y= 4(-1)+3= -1)

Draw a line trough points (1,7) and (-1, -1)

5 0
2 years ago
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