Answer:
the answer is option A
PLEASE MARK ME AS BRAINLY
Step-by-step explanation:
A.) P(defective | foo) = P(defective & foo)/P(foo)
4% = P(defective & foo)/30% . . . . . . . . . plug in the given data
0.04*0.30 = P(defective & foo) = 0.012 = 1.2%
The probability that a widget was produced at the foo factory and is defective is 1.2%.
b.) P(defective | foo) ≠ P(defective) (4% ≠ 5%), so the events P(defective) and P(foo) are NOT independent.
c.) P(foo | defective) = P(defective & foo)/P(defective)
P(foo | defective) = 1.2%/5% = 24%
The probability that a widget was produced at the foo factory given it is defective is 24%.
The answer is that 7.02 is 10.4% of 67.5
Answer:
95
Step-by-step explanation:
Being a sum of two elements that include units and tens, we can make the sums of the units first, and then add the tens together.
So, if we have 45+50, we can first separate the units: 5 + 0 =5
Then, we separate the tens: 4+5=9
Now, we only join the sums of the units and tens, and that will be the end result. 95
Answer:
relative minimum
Step-by-step explanation:
From f^''(x) = 12x we can take the integration to find out what f'(x) is:
Furthermore, we can substitute x = 1 for f''(x) to find out whether it's positive or negative
f''(1) = 12*1 = 12 > 0
So if x=1 is a critical point of f'(x) and f''(x=1) > 0 then that point is a relative minimum point
