Answer: squareroot of 58
You can solve this problem simply by using the <u>distance formula .</u> Using the distance formula we can solve this problem by just placing the numbers and then solving the equation.
Answer:
We know the distance (d) equation in terms of rate (r) and time (t) as:
d=rt
Step-by-step explanation:
We have given d=336 km and t= 12 hours, so we have: 336 km = 12t <-- this is our equation.
Divide each side by 12 to solve for t:
12t/12=336/12
t= 28 km/ hour
(4 * 5)2 - 6 + 3 = 37
Explanation:
(4 * 5) = 20
20 * 2 = 40
40 - 6 = 34
34 + 3 = 37
Answer:
The horizontal line is the x axis
the vertical line is the y axis
The first number is always the number of the x axis
Example.
(6,9)
6 is in the x axis
9 is in the y axis
find the number 6 in the x axis (the horizontal one) and then go up until the number 9.
Answer:
Therefore,
Wind speed of a Tornado when it travels 4 miles is 121.0 miles per hour.
Step-by-step explanation:
Given:
The wind speed near the center of a tornado is represented by the equation,
![S=93\log d+65](https://tex.z-dn.net/?f=S%3D93%5Clog%20d%2B65)
Where,
d = the distance, in miles
S = the wind speed, in miles per hour.
To Find:
S = ? at d = 4 miles
Solution:
We have
.........Given
Substitute d = 4 in above equation we get,
![S=93\log 4 + 65=93\times 0.602 +65=120.99](https://tex.z-dn.net/?f=S%3D93%5Clog%204%20%2B%2065%3D93%5Ctimes%200.602%20%2B65%3D120.99)
Rounding the answer to the nearest tenth we have
![S=121.0\ mph](https://tex.z-dn.net/?f=S%3D121.0%5C%20mph)
Therefore,
Wind speed of a Tornado when it travels 4 miles is 121.0 miles per hour.