Answer:
0.1257486
Step-by-step explanation:
Answer:
3) 0.30
The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given 'A' plays a sport
B work part time
Given P(A) = 0.48
P(B) = 0.40
P(A∩B) =0.12
P(A∪B)¹ =0.24
<u><em>Step(ii)</em></u>:-
By using conditional probability

and similarly 
The probability a randomly selected<em> student plays a sport</em> given they work part time
Now 

<u>Final answer</u>:-
The probability a randomly selected<em> student plays a sport</em> given they work part time = 0.30