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stich3 [128]
2 years ago
13

URGENT: Click on the graph to choose the correct answer to the equation. x > 2

Mathematics
1 answer:
Elan Coil [88]2 years ago
4 0

The graph of the inequality, x > 2 is the graph attached below.

<h3>How to Find the Graph of Inequality?</h3>

Given the inequality as, x > 2, it means all possible values of x must be greater than 2.

Thus, the graph that will show all possible values of x that would be greater than 2 would be a vertical line indicating the values are over 2 and upwards.

Therefore, the graph that represents x > 2 is shown in the image attached below.

Learn more about the graph of inequality on:

brainly.com/question/11234618

#SPJ1

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Scale Factor is just being multiplied to the width and length.

8 \times 1.25 =  a\\ 28 \times 1.25 = b \\ a = 10 \:  \:  \:  \:  \: b = 35
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the graph shows the number of wimbledon championships of several countries. Write the ration that compares the championships won
arlik [135]

Answer:

The ratio that compares the championships won by Australia to the total number won by the United States is equal to \frac{2}{5}

Step-by-step explanation:

Observing the graph

we know that

The championships won by Australia are 6

The championships won by the United States are 15

To find out the ratio, divide the championships won by Australia by the total number won by the United States.

so

\frac{6}{15}

Simplify

Divide by 3 boths (numerator and denominator)

\frac{2}{5}

Convert to percentage

\frac{2}{5}=0.40*100=40\%

that means

For every 2 championships won by Australia the United States won 5

or

The championships won by Australia are 40% of the championships won by the United States

4 0
3 years ago
6.
Strike441 [17]
The correct answer is B) 117
8 0
3 years ago
Which of the given numbers is not a Pythagorean triplets. *
Ludmilka [50]

Step-by-step explanation:

By Pythagoras' Theorem,

{c}^{2}  =  {a}^{2}  +  {b}^{2}

where c is always the largest number.

a and b can be interchangeable between the 2nd largest and the 3rd largest numbers.

Given a = 8, b = 15 and c = 17,

{a}^{2}  + b {}^{2}  =  {8}^{2}  +  {15}^{2}  \\  = 64 +  225 \\  = 289 \\   \\  {c}^{2}  =  {17}^{2}  \\  = 289

Since c^2 = a^2 + b^2 , 8 , 15 and 17 are pythagorean triplets.

Now let's move on to 9, 40 and 41.

{a}^{2}  +  {b}^{2}  =  {9}^{2}   +  {40}^{2}  \\  = 81 + 1600 \\  = 1681 \\  \\  {c}^{2}  =  {41}^{2}  \\  = 1681

Since c^2 = a^2 + b^2 , 9 , 40 and 41 are pythagorean triplets.

Last let's move on to 4,7 and 8.

{a}^{2}  +  {b}^{2}  =  {4}^{2}  +  {7}^{2}  \\  = 16 + 49 \\  = 65 \\  \\  {c}^{2}  =  {8}^{2}  \\  = 64

Since a^2+b^2 IS NOT EQUAL to c^2, 4,7 and 8 ARE NOT pythagorean triplets.

8 0
3 years ago
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