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mario62 [17]
3 years ago
11

20pts PLEASE HELP! Which polynomial is represented by the algebra tiles?

Mathematics
2 answers:
BartSMP [9]3 years ago
6 0
Quadratic trinomial is the answer for all of them since their exponent is 2 and have 3 unit
nikitadnepr [17]3 years ago
4 0

A picture would be nice.

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If the two solids have the same volume and height, find the area of one of the cross sections
Burka [1]

Answer:

18

Step-by-step explanation:

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5 0
4 years ago
C(n)=-6(-1/3) n-1 what’s the 2nd term in the sequence
Tpy6a [65]

Answer:

The second term is 3

Step-by-step explanation:

C(n)=-6(-1/3) n-1

The first term of the sequence

C(1) = -6(-1/3)1-1

C(1) = (2)-1

C(1) = 1

C(n)=-6(-1/3) n-1

The second term of the sequence

C(2) = -6(-1/3)2-1

C(2) = -6(-2/3)-1

C(2) = 4-1

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5 0
3 years ago
Read 2 more answers
There are 29 fewer bigstickers on the sticker sheet than the little stickers.there are 62 little stickers on the sheet .how many
mina [271]

Answer:

33

Step-by-step explanation:

you subtract 29 from 62 because there are 29 <u>less</u> big stickers

6 0
3 years ago
Tickets at a carnival cost $0.75
erma4kov [3.2K]
Answer: $14.75

I just did $0.75 x 7 = $5.25 and subtracted that from $20. Lmk if this helps or if my answer was incorrect!
8 0
2 years ago
Read 2 more answers
The only contents of a container are 4 blue disks and 8 green disks. If 3 disks are selected one after the other, and at random
-Dominant- [34]

Answer: B.  \dfrac{28}{55} .

Step-by-step explanation:

Given : Number of blue disks =4

Number of green disks = 8

Total disks = 12

Total number of combinations of drawing any 3 disks from 12 = ^{12}C_3

Number of combinations of drawing 1 blue and 2 green disks = ^{4}C_1\times^{8}C_2

Now , the probability that 1 of the disks selected is blue, and 2 of the disks selected are green will be :

\dfrac{^{4}C_1\times^{8}C_2}{^{12}C_3}\\\\=\dfrac{4\times\dfrac{8!}{2!6!}}{\dfrac{12!}{3!9!}}\\\\=\dfrac{4\times28}{220}\\\\=\dfrac{28}{55}

Hence, the correct answer is B.  \dfrac{28}{55} .

7 0
4 years ago
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