Consider that the three consecutive integers are:
least integer = n
middle integer = n + 1
greatest integer = n + 2
THe expression "three consecutive integers is 12 less than 4 times the middle integer" can be written as follow:
n + (n + 1) + (n + 2) = 4(n +1) - 12
In order to find the numbers, proceed as follow:
n + (n + 1) + (n + 2) = 4(n +1) - 12 cancel parenthesis
n + n + 1 + n + 2 = 4n + 4 - 12 simplify like terms
3n + 3 = 4n - 8 subtract 4n and 3 both sides
3n - 4n = - 8 - 3
-n = -11
n = 11
Hence, the three consecutive integers are:
n = 11
n + 1 = 12
n + 2 = 13
(p-8)(p+5)
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Given:
• Upper Base of trapezoid = 8 cm
,
• Lower base = 20 cm
,
• Length of one leg (also height) = 5 cm
,
• Length of other leg = 13 cm
Let's find the area of the trapezoid.
To find the area of the trapezoid, apply the formula:

Where:
A is the area
a is the length of upper base = 8 cm
b is the length of the lower base = 20 cm
h is the height = 5 cm
Plug in the values for a, b, and h to find the area, A:

Therefore, the area of the trapezoid is 70 cm^2