Perimeter of quadrant of a circle

1 answer:

7 0

Best Answer: the circumference of a circle is 2πr (where r= radius)
The arc length of a quadrant of a circle is a quarter of thecircumference, i.e. πr/2.
There are also the lengths of the 2 straight sides of the quadrant, and their lengths are both r. so the Perimeter of a quadrant= 2r + (πr/2)

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Answer:

$\textsf{12.} \quad y = 6x - 5$

$\textsf{17.} \quad y=-\dfrac{1}{4}x-2$

Step-by-step explanation:

<h3>Question 12</h3>

Find the slope of the line by substituting two points from the given table into the slope formula.

Define the points:

Let (x₁, y₁) = (2, 7)
Let (x₂, y₂) = (3, 13)

$\implies \textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{13-7}{3-2}=\dfrac{6}{1}=6$

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:

$\implies y-y_1=m(x-x_1)$

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<h3>Question 17</h3>

Given:

f(4) = 3
f(0) = -2

Therefore, two points on the line are:

(4, -3)
(0, -2)

The y-intercept is the y-value when x = 0.

Therefore, the y-intercept of the line is -2.

$\boxed{\begin{minipage}{6.3 cm}\underline{Slope-intercept form of a linear equation}\\\\$y=mx+b$\\\\where:\\ \phantom{ww}$\bullet$ $m$ is the slope. \\ \phantom{ww}$\bullet$ $b$ is the $y$-intercept.\\\end{minipage}}$