All categories

2 years ago

What's 4 dividend by 3736

Mathematics

2 answers:

yawa3891 [41]2 years ago

6 0

0.001070663811563 actually bc it's 4 dived by 3736

VLD [36.1K]2 years ago

5 0

The correct answer is 934

You might be interested in

Solve for z. Please show your work. 8z = 2z + 18

Nataly_w [17]

Answer:

x = 3

Step-by-step explanation:

8z = 2x + 18

6x = 18

x = 3

4 0

3 years ago

Read 2 more answers

Which ones do I select

Natalka [10]

Answer:

8(x) = 56 (x = 7) (x) + 5 3/4 = 8 3/4 (x = 3) x/2 = 3.5 (x = 7) Neither x - 2.56 = 0.44 (x = 3)

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Rus_ich [418]

Answer:

Step-by-step explanation:

yax2;

12+34+5+6=21 so y2+35

4 0

2 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

Simplify the equation.

Phoenix [80]

Answer:

C. $3j^{3}l$

Step-by-step explanation:

1) First you cancel $k^{2}$ because they are completely the same. then you take out the constants and simply.

2)You then have to use the Quotient Rule:

$\frac{x^{a} }{x^{b} } =x^{a - b}$

You should have ...

$3j^{6-3} l^{5-4}$

3) Simplify 6 − 3 to 3.

$3j^{3} l^{1}$

4) Simplify 5 − 4 to 1.

5) Use Rule of One: $x^{1} =x$

Answer is !!!

$3j^{3} l$

5 0

2 years ago