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mestny [16]
3 years ago
8

A fishing boat with two people on it runs out of gas while out in a bay. The people set off an emergency flare from a height of

2 meters above the water. The flare has an initial vertical velocity og 30 meters per second. How long does it take the flare to reach its maximum height? What is that height?
Mathematics
1 answer:
elixir [45]3 years ago
7 0

Answer:

Step-by-step explanation:

time taken to reach the max height is expressed according to the projectile equation;

tmax = u/g

Given u = 30m/s

g is the acceleration due to gravity = 9.81

t = 30/9.81

t = 3.0secs

hence it will take the flare 3.06secs to reach its maximum height.

Max height = u²/2g

Max height = 30²/2(9.81)

Max height = 900/19.62

Max height = 45.87m

If the people set off an emergency flare from a height of 2 meters above the water, the total height will be 45.87 + 2 = 47.87m

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ABF = EDG. GCF are equilateral. AG = 21 and CG 1/4 Find the total distance from A to B to C to D to E.
hjlf

The information given in the triangle shows that the total distance from A to B to C to D to E will be C. 84.

<h3>How to calculate the triangle?</h3>

From the information given, ABF = EDG, GCF are equilateral and AG = 21 while CG = 1/4.

The total distance from A to B to C to D to E will be:

= 21/CG

= 21 / 1/4

= 21/0.25

= 84

In conclusion, the correct option is 84.

Learn more about triangles on:

brainly.com/question/17335144

3 0
2 years ago
Consider the equation below.<br> -2(bx-5)=16 <br> Answer quick
Vlada [557]

Answer:

b= −3 /x

Step-by-step explanation:

Step 1: Add -10 to both sides.

−2bx+10+−10=16+−10

−2bx=6

Step 2: Divide both sides by -2x.

−2bx

−2x

=

6

−2x

b= −3 /x

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%2013%2B15%5Ctimes%203" id="TexFormula1" title="\sf 13+15\times 3" alt="\sf 13+15\times 3
Marat540 [252]

13 + 15 \times 3 \\  \\ first \: u \: need \: to \: multiply \:  \: 15 \times 3 \\  \\ second \\  \\ 13 + 45 \\  \\  = 58 \\ hope \:  \: it \:  \: helps

8 0
3 years ago
Read 2 more answers
MATH HELP PLZZZ 20 POINTS!!!!!
Alexxandr [17]
Number 1.) In game 1 he scored 180 points, In game 2 he scored 200 points this means the score went up , so now you have to add, ( Addition ).

180 + x = 200       |         x=?                    ,    well 180 + 20 = 200.


Since there is 20 points added to 180 which gives us 200 there is an 11.11% increase .
__________________________________________________



Number 2.) , In the next game he scored 200 points , it asks what is the decreased number?

how many numbers did his score drop?  200 - 180 = 20   |


Now we must work backwards , There is a loss in points , ( 20 ) , so there is an 10% decrease.    
  (200-180) / 180 * 100%  = 10%

                     20 / 200 * 100% = 10%

20 = The Answer with an 11.11% increase , there is a 10% decrease.

I hope this helps you a lot


6 0
3 years ago
Read 2 more answers
A spring is oscillating so that its length is a sinusoidal function of time. Its length varies from a minimum of 10 cm to a maxi
Hoochie [10]
Let the x(t) represent the motion of the spring as a function of time, t.

The length of the oscillating spring varies from a minimum of 10 cm to a maximum of 14 cm.
Therefore its amplitude is A = (14 - 10)/2 = 2.

When t = 0 s, x = 12 cm.
Therefore the function is of the form
x(t) = 2 sin(bt) + 12

At t=0, x(t) is decreasing, and it reaches its minimum value when t = 1.2 s.
Therefore, a quarter of the period is 1.2 s.
The period is given by
T/4 = 1.2
T = 4.8 s

That is,
b = (2π)/T = (2π)/4.8 = π/2.4 = 1.309

The function is
x(t) = 2 sin(1.309t) + 12
A plot of x(t) is shown below.

When x(t) = 13.5, obtain
2 sin(1.309t) + 12 = 13.5
sin(1.309t) = (13.5 - 12)/2 = 0.75
1.309t = sin⁻¹ 0.75 = 0.8481 or π - 0.8481
t = 0.8481/1.309 or t = (π - 0.8481)/1.309
  = 0.649 or 1.751
The difference in t is 1.751 - 0.649 = 1.1026.

This difference occurs twice between t=0 and t=8 s.
Therefore the spring length is greater than 13.5 cm for 2*1.1026 = 2.205 s.

Answer:
Between t=0 and t=8, the spring is longer than 13.5 cm for 2.205 s.

8 0
3 years ago
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