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balandron [24]
3 years ago
6

The desert temperature, H, oscillates daily between 40◦F at 5 am and 80◦F at 5 pm. Write a possible for- mula for H in terms of

????, measured in hours from 5 am.
Mathematics
1 answer:
strojnjashka [21]3 years ago
6 0

Answer:

H(t)=-20\text{cos}(\frac{\pi}{12}t)+60

Step-by-step explanation:

We have been given that the desert temperature, H, oscillates daily between 40◦F at 5 am and 80◦F at 5 pm. We are asked to write a formula H in terms of t, measured in hours from 5 am.

We will use cosine function to write our required formula.

y=A\text{cos}[B(x-C)]+D, where,

A = Amplitude,

\text{Period}=\frac{2\pi}{|B|}

C = Phase shift,

D = Vertical shift.

First of all, we will find amplitude using maximum and minimum values as:

A=\frac{\text{Maximum value}-\text{Minimum value}}{2}

A=\frac{80-40}{2}

A=\frac{40}{2}

A=20

Since period is 24 hours (5 am to 5 pm), so let us find B as:

24=\frac{2\pi}{|B|}

B=\frac{2\pi}{24}

B=\frac{\pi}{12}

\text{Vertical shift}=\frac{\text{Maximum value}+\text{Minimum value}}{2}

D=\frac{80+40}{2}=\frac{120}{2}=60

There is no phase shift.

Since temperature is minimum when t=0, so we will use negative cosine as:

H(t)=-20\text{cos}(\frac{\pi}{12}t)+60

Therefore, our required function would be H(t)=-20\text{cos}(\frac{\pi}{12}t)+60.

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Find the Roots of the following polynomial. <br><br> x3−5x2+6x = 0
ICE Princess25 [194]

Answer:

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

Step by step solution :

STEP

1

:

Equation at the end of step 1

((x3) - 5x2) - 6x = 0

STEP

2

:

STEP

3

:

Pulling out like terms

3.1 Pull out like factors :

x3 - 5x2 - 6x = x • (x2 - 5x - 6)

4 0
3 years ago
Read 2 more answers
At 3:30 in the afternoon in mid-September the Kimball Tower casts a shadow about 290 feet long when the sun's rays come down at
ioda

Answer:

203 feet.

Step-by-step explanation:

Please find the attachment.

Let h represent the height of the building.

We have been given that at 3:30 in the afternoon in mid-September the Kimball Tower casts a shadow about 290 feet long when the sun's rays come down at an angle about 35 degrees above the horizontal.    

We know that tangent relates opposite side of a right triangle to its adjacent side.

\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}

Upon substituting our given values in above formula, we will get:

\text{tan}(35^{\circ})=\frac{h}{290}

290*\text{tan}(35^{\circ})=\frac{h}{290}*290

290*0.70020753821=h

h=290*0.70020753821

h=203.0601860809

h\approx 203

Therefore, the building is approximately 203 feet high.

 

3 0
3 years ago
What’s the answer to this ?
gladu [14]

Answer:

x = 17

Step-by-step explanation:

Since the triangles are similar then corresponding angles are congruent.

∠ I = ∠P ← substitute values and solve for x

3x + 4 = 72 - x ( add x to both sides )

4x + 4 = 72 ( subtract 4 from both sides )

4x = 68 ( divide both sides by 4 )

x = 17

3 0
3 years ago
what is the relationship between 5.34 x 10^5 and 5.34 x 10^-2 is it greater or lesser than? for 5.34 x 10^5? will give brainlies
Romashka-Z-Leto [24]

the relationship between 5.34 x 10^5 and  5.34 x 10^-2

5.34 x 10^5 = 5.34*100000= 534000

5.34 * 10^-2  , for exponent -2 we move the decimal point 2 places to the left

5.34 x 10^-2= 0.0534

Now we compare 534000  and 0.0534

0.0534 is 10,000,000 times less than 534000

Or we can say  534000 is 10,000,000 times greater than 0.0534

5.34 x 10^5 is 10,000,000 times greater than 5.34 x 10^-2


3 0
2 years ago
Factor p^2−6−q·(p^2−6)^2
Olenka [21]

Answer:

(p^2−6) (1-q(p^2-6))

Step-by-step explanation:

p^2−6−q·(p^2−6)^2

Put parentheses around the P^2-6 at the beginning of the expression

(p^2-6) -q (p^2−6)^2

Factor out (p^2−6)

(p^2−6) (1-q(p^2-6))

5 0
2 years ago
Read 2 more answers
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