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quester [9]
3 years ago
15

I need help please thank u sm

Mathematics
1 answer:
gavmur [86]3 years ago
8 0
K= 8. If you look at the pattern each x value is multiplied by 8 to give you the y value. You could also solve it by:

40=k5
40/5=k
8=k

you could do this with any of the x or y values and still end up with 8.
You might be interested in
1/3y+1/4=5/12 i need 20 character
lys-0071 [83]
Y/3 + 1/4 = 5/12
4y/12 + 3/12 = 5/12
           4y/12 = 2/12
                4y = 2
                /4     /4
                  y = 1/2

Therefore y = 1/2

3 0
3 years ago
Solve the following system of equations by substitution. <br> 2x - y = 6<br> x + y = 6
m_a_m_a [10]

y=-x+6

2x-(-x+6)=6

3x=12

x=4

4+y=6

y=2

5 0
3 years ago
Read 2 more answers
Solve the inequality(s)<br> 2c &gt; 2 <br> d/6 ≥ 1 <br> r + 9 ≤ 23
tatiyna
Divide both sides by 2 for the first one.
2c/2>2/2
c>1
simplify both sides for the second 1 
1/6d>=1
6*(1/6d).=(6)*(1)
d>=6
For the last one 
subtract 9 from both sides
r+9-9<=23-9   so  that r<=14
 Hope this helps!





6 0
3 years ago
How could you informally prove to your friend that you are a member of the baseball team?
solniwko [45]

Answer:

D.) You can show your name printed on the team roster.Step-by-step explanation:

3 0
2 years ago
Prove :<br>sin²θ + cos²θ = 1<br><br><br>thankyou ~​
Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

\sf\longrightarrow sin^2\theta + cos^2\theta = 1

Imagine a right angled triangle with one of its acute angle as \theta .

  • The side opposite to this angle will be perpendicular .
  • Also we know that ,

\sf\longrightarrow sin\theta =\dfrac{p}{h} \\

\sf\longrightarrow cos\theta =\dfrac{b}{h}

And by Pythagoras theorem ,

\sf\longrightarrow h^2 = p^2+b^2 \dots (i)

Where the symbols have their usual meaning.

Now , taking LHS ,

\sf\longrightarrow sin^2\theta +cos^2\theta

  • Substituting the respective values,

\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\

\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\

\sf\longrightarrow \dfrac{p^2+b^2}{h^2}

  • From equation (i) ,

\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\

\sf\longrightarrow \bf 1 = RHS

Since LHS = RHS ,

Hence Proved !

I hope this helps.

5 0
2 years ago
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