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In-s [12.5K]
3 years ago
9

Sylvia translated the phrase into an algebraic expression and then evaluated it for n=5

Mathematics
2 answers:
frosja888 [35]3 years ago
5 0
The value you should get is 34. I'm assuming n is variable we should use. "the square of a number increased by 9" = "n^2+9" in an algebraic expression. then you plug in. 5^2+9 and then solve. 5^2=25. 25+9=34 
Black_prince [1.1K]3 years ago
5 0

Answer:

d:n+9=34

Step-by-step explanation:

because you have to take n=5 and increase by 9.

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Describe and correct the error a student made in finding the midpoint of CD with ​C(​4,5) and ​D(​1,​4).
Andru [333]

Using the given information, the midpoint of CD is (2.5, 4.5)

<h3>Midpoint of a line </h3>

From the question, we are to determine the midpoint of line CD

The midpoint of a line is given by the formula,

[(x₁ + x₂)/2 , (y₁ + y₂)/2]

From the given information, we are to find the midpoint of line CD with coordinates C(​4,5) and ​D(​1,​4)

∴ x₁ = 4

x₂ = 1

y₁ = 5

y₂ = 4

Putting the parameters into the formula for midpoint, we get

[(x₁ + x₂)/2 , (y₁ + y₂)/2]

[(4 + 1)/2 , (5 + 4)/2]

(5/2 , 9/2)

(2.5, 4.5)

Hence, the midpoint of CD is (2.5, 4.5)

Learn more on Midpoint of a line here: brainly.com/question/896396

#SPJ1

6 0
2 years ago
Angle ABC is formed by segments AB and BC on the following coordinate grid: A coordinate grid is shown from positive 6 to negati
Nadusha1986 [10]

Answer:

B) m∠ A'B'C' = m∠ABC

Step-by-step explanation:

A rotation does not change angle measure or side length.  It preserves congruence.

This means that the image angle, A'B'C', will be congruent to the pre-image angle, ABC.

5 0
3 years ago
Read 2 more answers
Please write the answer​
Travka [436]

\sf \dfrac{3^x - 5 \times 3^{(x-2)}}{3^{(x-3)}} \\ \\ \longrightarrow \sf \dfrac{ {3}^{x} }{ {3}^{(x - 3)}} - \frac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)}  \\ \\ \longrightarrow \sf {3}^{[x - (x - 3)]} - \dfrac{5}{ {3}^{(x - 3)} } \times {3}^{(x - 2)} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ {3}^{(x - 3)} } \times \dfrac{ {3}^{x}}{9} \\ \\ \longrightarrow \sf {3}^{3} - \dfrac{5}{ \bigg(\dfrac{ {3}^{x} }{ {3}^{3} }\bigg) } \times \dfrac{ {3}^{x}}{9}\\ \\ \longrightarrow \sf {3}^{3} - \dfrac{ ({3}^{3})( 5)}{ {3}^{x} } \times \dfrac{ {3}^{x}}{9}\\ \\ \sf \longrightarrow {3}^{3} - (5 \times 3) \\  \\ \longrightarrow \sf \: 27 - 15 \\  \\ \longrightarrow \leadsto{\underline{\boxed{\sf{ \pink{ 12}}}}}

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3 years ago
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step by step explanation:
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