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In-s [12.5K]
3 years ago
9

Sylvia translated the phrase into an algebraic expression and then evaluated it for n=5

Mathematics
2 answers:
frosja888 [35]3 years ago
5 0
The value you should get is 34. I'm assuming n is variable we should use. "the square of a number increased by 9" = "n^2+9" in an algebraic expression. then you plug in. 5^2+9 and then solve. 5^2=25. 25+9=34 
Black_prince [1.1K]3 years ago
5 0

Answer:

d:n+9=34

Step-by-step explanation:

because you have to take n=5 and increase by 9.

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What is the sum of one-sixth of x and 2.8?
Murljashka [212]
The answer is 2.8x! hope it helps
7 0
3 years ago
How do work this out
BabaBlast [244]
We can factor this by using grouping. Take the leading coefficient and multiply it by the constant. In this case we get 5*-7 = -35. 

Now we need 2 numbers that add to 2 and multiply to be -35. The numbers are -5 and 7.

So split the 2r into these two terms and group.

(5r^2 - 5r) + (7r - 7)

Factor both groups.

5r(r-1) + 7(r-1)

The factors of (r-1) can be added together to get the answer.

(r-1)(5r+7)
6 0
3 years ago
I wasn't in class so I need help solving the inequality 7/10n+14<49
NikAS [45]

Answer:

n<50

Step-by-step explanation:

7/2*5n + 14<49

7n/2*5+14<49

(7n)+(2*5)14/2*5 <49

7n+10*14/2*5 <49

7n+140/2*5 <49

7n+140/10 <49

7n+140 < 10*49

7n+140 < 490

(7n+140)+(-140)<490+(-140)

7n+140-140<490-140

7n<350

7n/7 < 350/7

n<2*5^2*7/7

n<2*5^2

n<2*25

n<50

8 0
3 years ago
Which represents where f(x) = g(x)?
Lyrx [107]

The <em><u>correct answer</u></em> is:

f(2) = g(2) and f(0) = g(0)

Explanation:

If f(x) = g(x), this means the values of the functions are the same when using the same numbers.  That means if we use 2 for x, then f(2) would need to be equal to g(2); if we use 0 for x, then f(0) would need to be equal to g(0).  This is the case in this option, so this option is correct.

3 0
3 years ago
Read 2 more answers
Slove the quadratic by factoring <br><br>x²-3x-16=-6​
creativ13 [48]

Answer:

x^(2)-3x-16=7x

Step-by-step explanation:

3 0
3 years ago
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