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Nadusha1986 [10]
3 years ago
8

URGENT!! 25 points. help on C please. this assignment is already late

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

7+(11-4\times 2)=10

Step-by-step explanation:

So, this question involves you to play around with the numbers and the operations a bit. I've come up with a solution, but perhaps there are others as well.

So, we have:

7\text{ } 11\text{ } 4\text{ } 2\text{ } =\text{ } 10

So, what we can do is, for instance, multiply 4 and 2. Subtract that into 11. And then add the difference to 7. Thus:

7+(11-4\times 2)=10

This is a true number sentence. Let's do it to make sure.

First, do the operations inside the parentheses.

Multiplication comes first, so multiply:

7+(11-8)=10

Again, do the parentheses first. Subtract:

7+(3)=10

Now add:

10=10

So our answer is correct :)

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Solving equations with variables on both sides <br><br><br> 7+9x=6x-2
katrin2010 [14]

Answer:

Here

Step-by-step explanation:

We move all terms to the left:

7+9x-(6x-2)=0

We get rid of parentheses

9x-6x+2+7=0

We add all the numbers together, and all the variables

3x+9=0

We move all terms containing x to the left, all other terms to the right

3x=-9

x=-9/3

x=-3

3 0
2 years ago
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-2(x+2=x-3(x+1)-1 please help me
Tcecarenko [31]
The solution would be x=0 because the statement is false.
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2 years ago
I need help with math!!
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Answer:

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Step-by-step explanation:

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2 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

7 0
3 years ago
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