A linear inequality to represent the algebraic expression is given as 492.46 - x ≥ 500
<h3>Linear Inequality</h3>
Linear inequalities are inequalities that involve at least one linear algebraic expression, that is, a polynomial of degree 1 is compared with another algebraic expression of degree less than or equal to 1.
In this problem, her minimum balance must not decrease beyond $500 or she will pay a fee.
where
The inequality to represent this can be written as
524.96 - 32.50 - x ≥ 500
Simplifying this;
492.46 - x ≥ 500
The linear inequality is 492.46 - x ≥ 500
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Answer:
x= 102 degrees
Step-by-step explanation:
It is an isosceles triangle, which means that it has two equal sides and angles, so the angles opposite of 3.3 are going to be the same or 39 degrees, which means, 39 + 39 is 78 and 180 - 78 is 102 and x=102 degrees.
a sequence is a function whose domain is the set of natural numbers.
natural numbers are all the negative and positive integers
Answer:
129.8 approximately
Step-by-step explanation:
So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.
So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.
My math is case sensitive.
X is the angle opposite to the side x.
Law of cosines formula is:

So we are looking for X.
We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).



Subtract 80 on both sides:


Divide both sides by -64:

Now do the inverse of cosine of both sides or just arccos( )
[these are same thing]

Time for the calculator:
X=129.8 approximately
Answer:
The correct expression is n + 8
The value of the expression = 5.3 + 8
The answer is 13.3
Step-by-step explanation:
The expression for eight increased by a number
Assume that the number is n
Increased eight by n means add n to eight
The correct expression is n + 8
When n = 5.3
Substitute 5.3 for the variable n
The value of the expression = 5.3 + 8
Simplify by adding 5.3 and 8
5.3 + 8 = 13.3
The answer is 13.3