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Levart [38]
3 years ago
10

PLZZZZZZZZZZ HELP ASAP THIS QUIZ IS 5MIN FROM BEING OVERDUE HELPPPPPP AND THE FIRST ONE TO ANSWER WILL GET THE BRAIN!!!!!!!!!!!!

Mathematics
2 answers:
just olya [345]3 years ago
8 0

her ratio of local calls was 9:5

scZoUnD [109]3 years ago
4 0

36/20

36/4 = 9

20/4 = 5

C) 9:5

Hope this Helps!!

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Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a
evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1=\frac{1}{2} *PQ*RM

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=\frac{1}{2} *SR*PN

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=\frac{1}{2}*PQ*h

S2=\frac{1}{2}*SR*h

Adding them together, we get the area of the whole trapezoid:

S=S1+S2=\frac{1}{2} (PQ+SR)h,

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}

Simplifying, we have

=>A= \frac{ah+2b_{1+C} }{2}

Factoring we have,

=> A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2}  \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}

 But, a+ b_{1} + c  is equal to b_{2}, the longer base of our trapezoid.

Hence, A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}

We have discussed two ways by which we can derive area of a trapezoid.

Read to know more about Trapezoid

brainly.com/question/4758162?referrer=searchResults

#SPJ10

5 0
2 years ago
The perimeter of a rectangle is 14cm. The length of the rectangle is 4 cm more than twice the width. Find the dimensions of the
sasho [114]

Answer:

length = 6 cm

width = 1 cm

Step-by-step explanation:

l = length

w = width

l = 4 + 2w

2(4 + 2w) + 2w = 14

8 + 4w + 2w = 14

8 + 6w = 14

6w = 6

w = 1

find length:

l = 4 + 2(1)

l = 6

3 0
3 years ago
If a wholesale price of an item is $250 and the markup is 25%. how much will you pay for the item
Eddi Din [679]
$250 x 0.25 = 62.5
62.5 + 250 == $312.50
you will pay $312.50
4 0
3 years ago
Plz help me!!!
disa [49]
~kites have adjacent sides equal~

x = 3x-12

move 3x to the other side as a negative number

-2x = -12

divide both sides by -2

-12 divided by -2 is 6

so, x is equal to 6

but, we aren't done yet because the questions asks for the value of angle b

substitute the value we found into the equation for angle b

3(6)-12

36-12

24

so, angle b has a value of 24 degrees
7 0
3 years ago
Two soup cans p and q are right circular cylinders. each can has the same height, 5 inches, but the radius of can p is 2 inches,
ASHA 777 [7]

Answer: B. 4

Sorry for the really late answer

Step-by-step explanation:

If the radius of a right circular cylinder is multiplied by k, and its height does not change, then the volume of the cylinder is multiplied by k². The radius of can Q is twice as great as the radius of can p. Therefor, the volume of can Q is 2², or 4 times larger than the volume of can p.

5 0
2 years ago
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