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sineoko [7]
3 years ago
11

Please help last one today

Mathematics
2 answers:
Fiesta28 [93]3 years ago
7 0
This is simple. You have to find the LCD here, on the fractions. The whole numbers you can just add together (whole numbers=5 and 2 in this case)

5+2=7. Your first number is 7

Find the LCD (Least common denominator) of 6 and 10. Do this by multiplying 6 by anything that comes to mind, and then multiply 10 by anything that comes to mind. The LEAST large outcome that is the SAME for both numbers is the LCD. 10 is easy, so let's only focus on 6. Think, what times 6 equals a number between 1-100 (just an example)
Well, 6*5=30. 10*3=30. DING!!

Now, your fractions look like: 5 5/30 divided by 2 1/30
What you do to the denominator you have to do to the numerator. Now, take 5 and multiply it by 5 (because for the denominator, 6*5=30)
Take 1 and multiply it by 3 (because for the denom. 10*3=30)
NOW you have: 5 and 25/30 divided by 2 and 3/30
Now just add!
5+2=7, 25 and 3=28, and the denominators don't change

Your answer is 7 and 28/30
~Hope this helps!
murzikaleks [220]3 years ago
4 0
7 28/30 is the answer
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A metalworker has a metal alloy that is 15​% copper and another alloy that is 75​% copper. How many kilograms of each alloy shou
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48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

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