The equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
<h3>How to determine the legs of the triangle?</h3>
The complete question is in the attached image
The given parameters are:
Area = 24
Legs = x and x + 2
The area of the triangle is calculated as:
Area = 0.5 * Base * Height
This gives
0.5 * x * (x + 2) = 24
So, we have:
0.5(x)(x + 2) = 24
Divide through by 0.5
(x)(x + 2) = 48
Expand
x^2 + 2x = 48
Subtract 48 from both side
x^2 + 2x - 48 = 0
Hence, the equations to calculate the legs are 0.5(x)(x + 2) = 24, x^2 + 2x - 48 = 0 and x^2 + (x + 2)^2 = 100
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Here are your points (-9,-8), (-6,-2), (-2,-6)
When adding fractions, you want the denominators to be the same number, so you have to multiply 31/2 by four for the numerator and denominator by 4 to have the denominators to both be 8. So the fraction on the left will be 124/8 + 1/8 =129/8. That fraction is in its simplest form.