Part A:
The given values in form of ordered pairs are:
(2,1), (3,1), (4,-3), (3,-3)
A relation can be a function if one value of x is paired with exactly one value of y. In this case, x value of 3 is paired with two y values 1 and -3. So this relation is not a function.
Part B:
f(h) = 15h + 5
f(8) can be found by substituting h=8 in above equation.
So,
f(8) = 15(8) + 5 = 125
h represents the number of hours and f(h) represents the earnings of Kylie. So f(8) shows that Kylie earned $125 from 8 hours of work in the cafe
Part C:
For r hours of work, we can write:
f(r) = 15r + 5
So, the ordered pair can represent this relation as:
(r, f(r))
or
(r, 15r+5)
Where is the question/example?
<span>5x²y + 2xy² + x²y
Combining like terms would be
6x²y + 2xy²
The two terms are now unique and cannot be combined any further. </span><span>
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