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zzz [600]
3 years ago
13

5-{3+2[5-4(64÷8)]-12}

Mathematics
2 answers:
kirill [66]3 years ago
4 0

You must follow the correct order of operations.

5 - {3 + 2[5 - 4(64 ÷ 8)] - 12} =

Start by doing the division in the innermost parentheses.

= 5 - {3 + 2[5 - 4(8)] - 12}

Now do the multiplication of 4 and 8.

= 5 - {3 + 2[5 - 32] - 12}

Now do the subtraction in the square brackets.

= 5 - {3 + 2[-27] - 12}

Multiply 2 by -27.

= 5 - {3 - 54 - 12}

Now do 3 - 54.

= 5 - {-51 - 12}

-51 - 12 is next.

= 5 - {-63}

= 5 + 63

= 68

Answer: 68

anygoal [31]3 years ago
3 0
The answer that I got was 29
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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
The following set of coordinates most specifically represents which figure? (−5, 6), (−1, 8), (3, 6), (−1, 4) (6 points) Paralle
Vladimir [108]

Answer:

Rhombus

Step-by-step explanation:

The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).

We use the distance formula to find the length of AB.

|AB|=\sqrt{(-1--5)^2+(8-6)^2}

|AB|=\sqrt{16+4}

|AB|=\sqrt{20}

The length of AD is

|AD|=\sqrt{(-1--5)^2+(6-4)^2}

|AD|=\sqrt{16+4}

|AD|=\sqrt{20}

The length of BC is:

|BC|=\sqrt{(-1-3)^2+(8-6)^2}

|BC|=\sqrt{16+4}

|BC|=\sqrt{20}

The length of CD is

|CD|=\sqrt{(-1-3)^2+(6-4)^2}

|CD|=\sqrt{16+4}

|CD|=\sqrt{20}

Since all sides are congruent the quadrilateral could be a rhombus or a square.

Slope of AB=\frac{8-6}{-1--5}=\frac{1}{2}

Slope of BC =\frac{8-6}{-1-3}=-\frac{1}{2}

Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be  a square. It is a rhombus

7 0
3 years ago
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Hi. What is the smallest number that can be written in 6 ways as the sum of the squares of 3 primes? Also, please list them as w
Fed [463]

2019 is the smallest number.

Here are the ways:

7^2+11^2+43^2

7^2+17^2+41^2

13^2+13^2+41^2

11^2+23^2+37^2

17^2+19^2+37^2

23^2+23^2+31^2



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3 years ago
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malfutka [58]

Answer:

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LuckyWell [14K]

Answer:

9/16

Step-by-step explanation:

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2 years ago
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