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Amiraneli [1.4K]
3 years ago
7

una escalera de 12ft de longitud esta apoyada contra una pared, de modo que su base se encuentra a 4 ft de la pared a nivel del

suelo.cual es la altura de la pared hasta donde esta recargada la pared?​
Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

Step-by-step explanation:

Altura = 11.312 pies

i) La escalera que descansa contra la pared formará un triángulo en ángulo recto.

ii) la escalera formará la hipotenusa del triángulo rectángulo dado por h = 12 pies.

iii) La base está dada por 4 pies.

iv) de la fórmula del triángulo en ángulo recto.

   base  = altura = \sqrt{hipotenusa^{2}\hspace{0.15cm}- \hspace{0.15cm} base^{2} }  = \sqrt{12^{2}\hspace{0.15cm} - \hspace{0.15cm}4^{2}  } = \sqrt{144\hspace{0.15cm} - \hspace{0.15cm}16} = \sqrt{128} = \hspace{0.15cm}8\sqrt{2} = 8\times1.414 = 11.312 pies

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