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Serhud [2]
3 years ago
15

Which relationships have the same constant of proportionality between yyy and xxx as the equation 3y=27x3y=27x3, y, equals, 27,

x?
Mathematics
1 answer:
topjm [15]3 years ago
4 0

Answer:

See Explanation

Step-by-step explanation:

The options are not given; however, the solution is as follows;

3y = 27x

Required

Determine relationships with the same constant of proportionality (k)

3y = 27x

Divide both sides by 3

\frac{3y}{3} = \frac{27x}{3}

y = \frac{27x}{3}

y = 9x

The relationship between y, x and k is:

y = kx

Comparing y = kx with y = 9x; then

k = 9

<em>Hence, any of the options with k=9 answers the question.</em>

<em>Take for instance:</em>

2y = 18x

Dividing both sides by 2 gives

y = 9x and hence; k = 9

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kotegsom [21]

Let us take costs of a piece of toast = $t, , one bagel cost=$b and a muffin cost=$m.

Larry

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2t+b=1.30   -------------equation(1)

Let us solve the equation(1) for t in terms of b, because we need to find one bagel cost.

Subtracting b from both sides we get

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2t= 1.30-b

Dividing by 2 on both sides.

2t/2= (1.30-b)/2

t= (1.30-b)/2

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A bagel and a muffin cost = $2.50.

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Solving equation for m in terms of b, we get

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Moe

A piece of toast, two bagels, and three muffins cost = $6.95

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Multiplying each term by 2 to get rid 2 from denominator of (1.30-b).

2*(1.30-b)/2 + 2*2b + 2*3(2.50-b) = 2*6.95

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Combining like terms

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Subtracting 16.30 from both sides.

-3b +16.30-16.30 = 13.90-16.30.

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Dividing both sides by -3.

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Answer:

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