Answer:
Reflection
Step-by-step explanation:
(x, y) --> (x, -y) is a reflection over the x-axis
Answer:
x+13
Step-by-step explanation:
5x+2(3-2x)+7
5x+6-4x+7 <em>open</em><em>ing</em><em> </em><em>brac</em><em>ket</em><em>.</em><em>.</em><em>.</em>
<em>now </em><em>collect</em><em> </em><em>like</em><em> </em><em>terms</em><em>.</em><em>.</em><em>.</em>
5x-4x+6+7
x+13
Answer:
m∡GHI = 21°
Step-by-step explanation:
Since the lines are intersecting, GHI and JHK are opposite angles, so they are the same measure.
That means you can set them equal to each other
x + 7 = 3x - 21
x = 14
Now plug x into GHI
14 + 7 = 21
m∡GHI = 21°
Answer:
the third one 10 cm, 9cm 9cm
Answer:
54 ft^2
(54 in green box; 2 in grey box)
Step-by-step explanation:
We have 2 similar triangles, ABC and DEF.
The area of triangle DEF is given as 6 sq ft.
Side BC of triangle ABC measures 12 ft.
The corresponding side to BC in triangle DEF is EF. It measures 4 ft.
That gives us a scale factor from triangle DEF to triangle ABC.
<em>To find the scale factor between two similar polygons, divide the length of a side of the second polygon by the length of the corresponding side of the first polygon.</em>
scale factor = BC/EF = (12 ft)/(4 ft) = 3
The scale factor of side lengths is 3.
The ratio of the areas is the square of the scale factor.
ratio of areas = 3^2 = 9
Now multiply the area of the first triangle (DEF) by the ratio of areas to get the area of the second triangle (ABC).
area of triangle ABC = 9 * (area of triangle DEF)
area of triangle ABC = 9 * (6 sq ft)
area of triangle ABC = 54 sq ft
Answer: 54 ft^2
(54 in green box; 2 in grey box)
