Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
Explanation:
#include<iostream>
#include<string.h>
using namespace std;
char *removestring(char str[80])
{
int i,j,len;
len = strlen(str);
for( i = 0; i < len; i++)
{
if (str[i] == ' ')
{
for (j = i; j < len; j++)
str[j] = str[j+1];
len--;
}
}
return str;
}
int main ()
{
char str[80];
cout << "Enter a string : ";
cin.getline(str, 80);
strcpy(removestring(str), str);
cout << "Resultant string : " << str;
return 0;
}
In this program the input is obtained as an character array using getline(). Then it is passed to the user-defined function, then each character is analyzed and if space is found, then it is not copied.
C++ does not allow to return character array. So Character pointer is returned and the content is copied to the character array using "strcpy()". This is a built in function to copy pointer to array.
Answer:
MIDI might be a better option.
Explanation:
USB is much faster, and just as reliable as a MIDI cable. An external disk drive with a USB connection transmits data thousands of times faster than a single MIDI instrument with no problems! If you want to use very long cables, for on-stage work for example, MIDI might be a better option.
Answer:
<em>Empirical technical </em>research has a fundamental objective, which is to provide objective and independent information on the quality of the product to the interested party or stakeholder. It is one more activity in the quality control process.
Explanation:
Testing is basically a set of activities within software development. Depending on the type of tests, these activities may be implemented at any time during said development process. There are different software development models, as well as test models. Each one has a different level of involvement in development activities.
In a full penetration testing process, there are pre-instances to run this tool, but to take the first steps it is probably the best way to start. Nmap is a network scanning tool that allows you to identify what services are running on a remote device, as well as the identification of active computers, operating systems on the remote computer, existence of filters or firewalls, among others.
In simple words, when a server or device is going to be attacked, the attacker can carry out different attacks depending on the service: it is not the same to damage a web server, a database server or a perimeter router. Therefore, in any deployment, the first step will be to identify the services in the infrastructure, to decide how to proceed and, considering that in a penetration test the steps of an attacker are “imitated”, it will also be started in the same way.
Simulation predicts possible problems before they occur
