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In-s [12.5K]
3 years ago
11

Find (x.y). y=6x-11 and -2x-3y=-7

Mathematics
1 answer:
mezya [45]3 years ago
7 0

(-1.3,-18.8)

you would start by substituting y=6x-11 into -2x-3y=-7

so it would look like

-2x-3(6x-11)=-7

once you solve for x you would then take the x value of -1.3 and put it into the equation y=6x-11 so it would look like this

y=6(-1.3)-11

which would get you y=-18.8

to check you would put both the x and y value back into -2x-3y=-7 and boom answer

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189

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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2 years ago
On the graph below are three points X, Y, and Z. Write the coordinates for the given dilation.
Julli [10]

ANSWER

( -  \frac{3}{2} , - 1)

EXPLANATION

From the graph, the coordinates of Y are:

(3,2)

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(x,y)\to( - \frac{1}{2}  x, -  \frac{1}{2} y)

To find the coordinates of Y', we plug the coordinates of Y.

Y(3,2)\to \: Y'( - \frac{1}{2}  (3), -  \frac{1}{2}(2) )

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The first choice is correct.

6 0
3 years ago
What is 34% written as a ratio?
ZanzabumX [31]
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5 0
3 years ago
Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?
Eddi Din [679]
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|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }

The magnitude of vecor v is given to be 10. So we can write:

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Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector. 

The point in option d, satisfies the equation.

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Thus, the answer to this question is option D
7 0
3 years ago
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