Answer:
10m.
Step-by-step explanation:
Since there is no remainder we simply need to find the least common multiple of each of the lengths of Janice and Jasmin's strings until we find a multiple that matches for each. Like so...
2*1 = 2 5*1 = 5
2*2 = 4 5*2 = 10
2*3 = 6
2*4 = 8
2*5 = 10
Finally, we have found the first common multiple which is 10m. That means that the shortest equal length for both Janice's and Jasmin's ribbon is 10m.
The distributive property: a(b + c) = ab + ac
7 × 7 = 7 × (10 - 3) = (7)(10) - (7)(3) = 70 - 21 = 49
7 × 7 = 7 × (5 + 2) = (7)(5) + (7)(2) = 35 + 14 = 49
ABC ≅ QPR because it is just a mirror image to ABC.
hope my answer helped out! Have a nice day Aaronbenjakedor!
Using the binomial distribution, it is found that there is a 0.056 = 5.6% probability that more than 7 will make a purchase.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- There are 12 customers, hence n = 12.
- The probability of any of them making a purchase is of p = 0.4.
The probability that more than 7 will make a purchase is given by:
P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12).
Hence:






Then:
P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.042 + 0.012 + 0.02 + 0 + 0 = 0.056.
0.056 = 5.6% probability that more than 7 will make a purchase.
More can be learned about the binomial distribution at brainly.com/question/24863377
let's firstly convert the decimal to a fraction, namely a rational.
so we have one decimal, thus let's use 1 zero at the denominator and lose the dot on the numerator.

so then, what rationals are between -8/5 and +8/5? well, a huge amount hmmm let's pick two.
![\bf \boxed{-\cfrac{8}{5}}\rule[0.35em]{9.5em}{0.25pt}~~-\cfrac{3}{5}~~\rule[0.35em]{2em}{0.25pt}0\rule[0.35em]{10em}{0.25pt}~~\cfrac{6}{5}~~\rule[0.35em]{2.5em}{0.25pt}\boxed{\cfrac{8}{5}}](https://tex.z-dn.net/?f=%5Cbf%20%5Cboxed%7B-%5Ccfrac%7B8%7D%7B5%7D%7D%5Crule%5B0.35em%5D%7B9.5em%7D%7B0.25pt%7D~~-%5Ccfrac%7B3%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2em%7D%7B0.25pt%7D0%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D~~%5Ccfrac%7B6%7D%7B5%7D~~%5Crule%5B0.35em%5D%7B2.5em%7D%7B0.25pt%7D%5Cboxed%7B%5Ccfrac%7B8%7D%7B5%7D%7D)