Pretty sure it’s gonna Y=4x
Answer:
x≤11
Step-by-step explanation:
x+5<17, I can subtract 5 on both sides so
x+5<17
<u> -5 -5</u>
x<12
that's wrong though because my x needs to make my answer less than x to make the statement true since we're looking for a value that is less than 17 not less than or equal to 17. So in conclusion, if x≤11 ( if x is less than or equal to 11), my statement will be true because 11+5<17=16<17, which is true. Even 10 or less is fine because it will still be smaller than 17 and that will keep my statement balanced.
We know that
<span>Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another.
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.
</span>we have that
<span>Circle 1 is centered at (4,3) and has a radius of 5 centimeters
</span><span> Circle 2 is centered at (6,-2) and has a radius of 15 centimeters
</span>
step 1
<span>Move the center of the circle 1 onto the center of the circle 2
</span>the transformation has the following rule
(x,y)--------> (x+2,y-5)
so
(4,3)------> (4+2,3-5)-----> (6,-2)
so
center circle 1 is now equal to center circle 2
<span>The circles are now concentric (they have the same center)
</span>
step 2
A dilation is needed to increase the size of circle 1<span> to coincide with circle 2
</span>
scale factor=radius circle 2/radius circle 1-----> 15/5----> 3
radius circle 1 will be=5*scale factor-----> 5*3-----> 15 cm
radius circle 1 is now equal to radius circle 2
A translation, followed by a dilation<span> will map one circle onto the other, thus proving that the circles are similar</span>
The Missing side of the right triangle is 10
