Answer is D
After dilation the image remain same but it is stretched or shrinked to the original size.
That means the ratio of the sides and the angles between the sides remain same .
Here we did dilation of ABCD which made it to EFGH.
Hence the ratio of the corresponding sides of the original rectangle ABCD should remain same even after dilation.
the corresponding sides are : AB and EF
BC and FG
CD and GH
DA and HE
* Let us find ratio of the sides AB and BC
given that AB= 10 and BC= 14
AB/BC= 10/14 = 5 /7 ( 10 and 14 both are multiple of 2 so we reduced them by a factor of 2 )
* the raio of the corresponding sides EF and FG should be same ( 5/7)
in the option D EF= 25 and FG= 35
so EF/FG= 25/35 = 5 /7 ( both are multiple of 5 so we reduced them by the factor of 5 )
Since ratio of the corresponding sides are coming out to be same for the EFGH given in option D it should be the dilation of the ABCD
Answer:
m=7/2
Step-by-step explanation:
7x-2y=14
2y=7x-14
y=7/2x-14/2
y=7/2x-7
y=mx+b where m=slope and b=y-intercept,
the slope is 7/2
Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
Answer:
c
Step-by-step explanation:
4 us customary cups
in one quart
