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3 years ago

For the graph above what is the approximate y-value of the point of intersection

Mathematics

2 answers:

Sauron [17]3 years ago

4 0

Answer:

$3$

Step-by-step explanation:

we know that

The x-coordinate of the point of intersection belong to the interval----> $[-1,0]$ (closest to $-1$ )

The y-coordinate of the point of intersection belong to the interval----> $[2,3]$ (closest to $3$ )

therefore

the answer is $3$

mash [69]3 years ago

3 0

It's hard to say, because the blue section doesn't have a definite line like the red does. However, the y-value poi looks to be about 2.5, but out of your choices I would choose 3.

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Equivalent fractions- 3/4=/8

mamaluj [8]

You just have to multiply both by 2, and 3/4 = 6/8. 3 times 2 equals 6, and 4 times 2 equals 8. I hope I helped! :-)

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3 years ago

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The vertex form of the equation of a parabola is y= 3(x - 4)^2 -22. What is the standard form of the equation

Sunny_sXe [5.5K]

Answer:

option A

Step-by-step explanation:

We can find the standard form by expanding the equation:

y = 3(x-4)^2 - 22

y = 3(x^2 - 8x + 16) - 22

y = 3x^2 - 24x + 48 - 22

y= 3x^2 - 24x + 26

So the correct option is option A

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3 years ago

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The length of a field in yards is a function f( n ) of the the length in n feet. Write a function rule for this situation.

Phantasy [73]

Answer:

$f(n)=\frac{1}{3}n$

Step-by-step explanation:

To convert from feet to yards, divide by the value 3.

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3 years ago

Find the solution to each equation.

Alex

Answer:

k = 16

p = 21

m = 24

c = 23

g = 18

Step-by-step explanation:

All you had to do was divide the product by the number with the variable

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3 years ago

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not. Determ

Hunter-Best [27]

Answer:

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A recent survey showed that among 100 randomly selected college seniors, 20 plan to attend graduate school and 80 do not.

This means that $n = 100, \pi = \frac{20}{100} = 0.2$

68% confidence level

So $\alpha = 0.32$ , z is the value of Z that has a pvalue of $1 - \frac{0.32}{2} = 0.84$ , so $Z = 0.995$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 - 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.16$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2 + 0.995\sqrt{\frac{0.2*0.8}{100}} = 0.24$

The 68% confidence interval for the population proportion of college seniors who plan to attend graduate school is (0.16, 0.24).

4 0

3 years ago