A line passes through the point (8,4) and is parallel to 9x+3y=12 what is the equation of the line

ANSWER PLEASE! WILL MARK BRAINLIEST! OFFERING 30 POINTS!

SSSSS [86.1K]

Answer:

C

Step-by-step explanation:

Work backwards. You are given -3 , -30 for C. If you add -3 + 3 and the divide it by 2 , you get 0. If you add 8 + -20 and divide by 2 you get -6 , so the answer is C.

7 0

3 years ago

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The probability that Aaron goes to the gym on Saturday is 0.8

Ronch [10]

Answer:

The probability that Aaron goes to the gym on exactly one of the two days is 0.74

Step-by-step explanation:

Let P(Aaron goes to the gym on exactly one of the two days) be the probability that Aaron goes to the gym on exactly one of the two days.

Then

P(Aaron goes to the gym on exactly one of the two days) =

P(Aaron goes to the gym on Saturday and doesn't go on Sunday) +

P(Aaron doesn't go to the gym on Saturday and goes on Sunday)

If Aaron goes to the gym on Saturday the probability that he goes on Sunday is 0.3. Then If Aaron goes to the gym on Saturday the probability that he does not go on Sunday is 1-0.3 =0.7

Since the probability that Aaron goes to the gym on Saturday is 0.8,

P(Aaron goes to the gym on Saturday and doesn't go on Sunday) =

P(the probability that Aaron goes to the gym on Saturday)×P(If Aaron goes to the gym on Saturday the probability that he does not go on Sunday)

=0.8×0.7=0.56

The probability that Aaron doesn't go to the gym on Saturday is 1-0.8=0.2

And if Aaron does not go to the gym on Saturday the probability he goes on Sunday is 0.9.

Thus, P(Aaron doesn't go to the gym on Saturday and goes on Sunday) = P(The probability that Aaron doesn't go to the gym on Saturday)×P(if Aaron does not go to the gym on Saturday the probability he goes on Sunday)

=0.2×0.9=0.18

Then

P(Aaron goes to the gym on exactly one of the two days) =0.56 + 0.18 =0.74

5 0

3 years ago

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Is 89.2 greater than 89.200

Semenov [28]

Answer:

No, they are equal values

Step-by-step explanation:

89.2 can also be written as 89.200, the extra zeroes do not change the value

6 0

3 years ago

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Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity.

Arturiano [62]

The Pythagorean theorem is one that can be used to determine the third unknown side of a given right-angled triangle. Thus the answers required are:

A pair of similar triangles formed are ΔABD and ΔADC
Segment AD is a perpendicular bisector of segment BC, and also bisects angle A in two equal measures
Segment AD = 3

A right-angled triangle is one which has the measure of one of its internal angles equal to $90^{o}$ . Thus to determine the value of one of its unknown sides, the Pythagoras theorem can be used.

Pythagora theorem states that: for a right-angled triangle,

$/Hypotenus/^{2}$ = $/Adjacent 1/^{2}$ + $/Adjacent 2/^{2}$

Thus from the given question, we have;

Part A: A pair of similar triangles formed are ΔABD and ΔADC.

Part B: In the given triangle, segment AD is a perpendicular bisector of segment BC. Thus segment AD also bisects angle A in two equal measures. So triangle ABC is now divided into two equal pairs i.e ΔABD and ΔADC.

Part C: Given that: If DB = 9 and DC = 4, find the length of segment DA.

Let segment AD be represented by x, so that;

from ΔABC,

$/Hypotenus/^{2}$ = $/Adjacent 1/^{2}$ + $/Adjacent 2/^{2}$

$/13/^{2}$ = $/Adjacent 1/^{2}$ + $/Adjacent 2/^{2}$

Thus the appropriate Pythagorean triple for this question is 5, 12, 13.

So that AB = 12, AC = 5 and BC = 13

Let segment AD be represented by x.

Thus from triangle ADC, applying the Pythagoras theorem we have;

$5^{2}$ = $x^{2}$ + $4^{2}$

25 - 16 = $x^{2}$

$x^{2}$ = 9

x = 3

Therefore, segment AD is 3.

For more clarifications on Pythagoras theorem, visit: brainly.com/question/343682

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Kindly contact a 1-on-1 tutor if more explanations are needed.

6 0

2 years ago

A cubic polynomial with zeros at -2, 1, and 4 passes through (2, -56). What is the

victus00 [196]

Answer:

6, -5 and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the cubic polynomial in standard form.

3 0

2 years ago