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Monica [59]
4 years ago
14

The area of a rectangular painting is 4536 cm squared .if the width of the painting is 56cm, what is it’s length?

Mathematics
1 answer:
Novay_Z [31]4 years ago
5 0

Answer: 81

Step-by-step explanation: 4536 ÷ 56 = 81

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WRITE THE EQUATION BELOW IN SLOPE-INTERCEPT FORM;<br><br> 14x=6Y-12
valentinak56 [21]

The sllope-intercept form:

y=mx+b


6y-12=14x          <em>add 12 to both sides</em>

6y=14x+12      <em>divide both sides by 6</em>

y=\dfrac{14}{6}x+\dfrac{12}{6}\\\\\boxed{y=\dfrac{7}{3}x+2}

5 0
3 years ago
. Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x-
Ksenya-84 [330]

Answer:

A. x = 16 , y = 34

B x = 2000, y = 1000

Step-by-step explanation:

Solution:-

- We will first define our variables ( x and y ) as follows:

                     x: The number of "nickels" in the jar

                     y: The number of "dimes" in the jar.

- Nest we will write down the rates of nickel and dime in dollar equivalent as ( P_n and P_d, respectively )  as follows:

                    P_n = $0.05  ... ( 5 cents )

                    P_d = $0.10   ... ( 10 cents )

- We are told that the jar contains a total of "50" coins comprised of nickel and dimes. Since, we don't know the exact amount of nickel and dimes in the jar. We will express the statement mathematically using the previously defined variables as follows:

                     x + y = 50     ... Eq1

- Secondly, the total worth of the jar is given to be " $4.2 ". The respectively value of each coin was iterated above. We will compute the total worth of the jar by expressing in terms of x and y as follows:

                    P_n*x + P_d*y = 4.2\\\\0.05x + 0.1*y = 4.2  ... Eq 2

- We have two equations [ Eq1 and Eq2 ] comprising of two variables. We can solve them simultaneously for a unique solution ( x and y ).

- To solve by elimination. We will first multiply the [ Eq1 ] by "- 0.1 " throughout as follows:

                    -0.1x - 0.1y = -5\\\\0.05x + 0.1y = 4.2

- Now we will add the two equations and eliminate the variable " y " and solve for " x ":

                    -0.05x = -0.8\\\\x = 16

- Now plug the value of " x " in either of the derived equations and solve for "y":

                    y = 50 - 16\\y = 34

Answer: There are 16 nickels and 34 dimes in the jar of total worth $4.2.

- We will first define our variables ( x and y ) as follows:

                     x: The number of "sodas" sold

                     y: The number of "hot dogs" sold.

- Nest we will write down the rate charged for soda and hot-dogs equivalent as ( P_s and P_h, respectively )  as follows:

                    P_s = $2 / soda

                    P_h = $3 / hot-dog

- We are told that " 3000 " sodas and hot-dogs were sold at the concession stand . Since, we don't know the exact amount of sodas and hot-dogs sold. We will express the statement mathematically using the previously defined variables as follows:

                     x + y = 3000   ... Eq1

- Secondly, the total amount expressed on the receipts after selling "x" many sodas and " y " many hot--dogs was " $7000 ". The respectively value of each commodity sold was iterated above. We will compute the total value of items sold by expressing in terms of x and y as follows:

                    P_s*x + P_h*y = 7000\\\\2x + 3y = 7000 ... Eq 2

- We have two equations [ Eq1 and Eq2 ] comprising of two variables. We can solve them simultaneously for a unique solution ( x and y ).

- To solve by elimination. We will first multiply the [ Eq1 ] by "-2 " throughout as follows:

                    -2x - 2y = -6000\\\\2x + 3y = 7000

- Now we will add the two equations and eliminate the variable " x " and solve for " y ":

                    y = 1000

- Now plug the value of " y " in either of the derived equations and solve for "x":

                    x = 3000 - 1000\\\\x = 2000

Answer: The concession sold 2000 sodas and 1000 hot-dogs of total worth $7000.

8 0
3 years ago
The chance of rain is 20%, the chance of it being sunny is 60%, and the chance of it
Charra [1.4K]

Answer:

0.6 = 60% probability that it is either sunny or rainy.

Step-by-step explanation:

We solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Rain

Event B: Sun

The chance of rain is 20%

This means that P(A) = 0.2

The chance of it being sunny is 60%

This means that P(B) = 0.6

The chance of it being sunny and rainy at the same time is 10%.

This means that P(A \cap B) = 0.1

Calculate, the probability that it is either sunny or rainy.

This is:

P = P(A) + P(B) - 2P(A \cap B) = 0.2 + 0.6 - 0.2 = 0.6

0.6 = 60% probability that it is either sunny or rainy.

3 0
3 years ago
Who can help me d e f thanks​
12345 [234]

d)

y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}

Product rule:

y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'

Chain and power rules:

y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'

Power rule:

y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)

Now simplify.

y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}

y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}

e)

y = \dfrac{3bx + ac}{\sqrt{ax}}

Quotient rule:

y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}

y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}

Power rule:

y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}

Now simplify.

y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}

y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}

y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}

f)

y = \sin^2(ax+b)

Chain rule:

y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'

y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'

y' = 2a \sin(ax+b) \cos(ax+b)

We can further simplify this to

y' = a \sin(2(ax+b))

using the double angle identity for sine.

7 0
2 years ago
14,345,678 (nearest hundred thousand) * what’s is the answers
Readme [11.4K]

Answer:

14,300,000

Step-by-step explanation:

Starting off with 14 million, you haven't reached the 100 thousands or below yet where you should start. The next digit, 3, is in the 100 thousands place and the digit next to it is four. When you're rounding, if the digit is greater than five, then you round up. (example: if the number you're rounding is 67, seven is greater than five so you would round it to 70.) If the digit you are rounding is smaller than 5 then you would round down. (Example: if the number you're rounding is 34, then you would round down because four is smaller than five or higher.) Since in your problem, you have 345,678, (we've already discussed the 14 million part in the beginning) 4 is smaller than 5 or higher so it would round 14,345,678 to 14,300,678. However, since we've already rounded the part we meant to do, every digit after would turn to 0. The final result would be 14,300,000.

8 0
4 years ago
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