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ozzi
3 years ago
14

Determine whether −2 is a zero (root) of the function:

Mathematics
2 answers:
lianna [129]3 years ago
5 0

Answer:

The answer to your question is No

Step-by-step explanation:

Data

function f(x) = 2x³ + x² - 10x - 12

To know if a number is a root of a function, evaluate the function on that number, if the result is zero, then that number is a root.

Substitution          

               f(-2) = 2(-2)³ + (-2)² - 10(-2) - 12

Simplification          

               f(-2) = 2(-8) + 4 + 20 - 12

               f(-2) = -16 + 4 + 20 - 12

               f(-2) = -28 + 24

               f(-2) = -4

-2 is not a root that the function.

gregori [183]3 years ago
4 0

Answer:

No

Step-by-step explanation:

Using factor theorem

If the remainder is 0, it is a root

2(-2)³ + x(-2)² − 10(-2) − 12

-4

Since the remainder is non-zero, it is not a root

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3 0
3 years ago
The function Q(x)=2x^2-kx+18. For what value of k does Q(x) have one distinct real solution? (NEEDS TO BE DONE WITHIN 2 HOURS!)
Aliun [14]

Answer:

k = 12

Step-by-step explanation:

Given:

The equation Q(x)=2x^2-kx+18

To find:

Value of k = ? for which the given equation has one distinct real solution.

Solution:

The given equation is a quadratic equation.

There are always two solutions of a quadratic equation.

For the equation: ax^{2} +bx+c=0 to have one distinct solution:

b^2 - 4ac = 0

Here,

a = 2,

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Putting the values, we get:

(-k)^2 - 4\times 2\times 18 = 0\\\Rightarrow k^2 = 18\times 8\\\Rightarrow k^2 =144\\\Rightarrow k = 12

The equation becomes:

Q(x)=2x^2-12x+18

And the one root is:

2(x^2-6x+9 ) = 0\\\Rightarrow 2(x-3)^2=0\\\Rightarrow x = 3

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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