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Rasek [7]
3 years ago
11

Can you help me solve x-1<-1 or 8x+9≥41

Mathematics
2 answers:
Rus_ich [418]3 years ago
7 0
Looks good except the second part I think may x<_4 so same answer just a different direction because you had to divide
Elza [17]3 years ago
3 0
For the first one:
x-1<span><-1
Add one on both sides.
x</span><span><0

For the second one:
8x+9</span><span>≥41
Subtract nine on both sides.
8x+</span><span>≥32
Divide by eight on both sides.
x</span><span>≥4

HOPE THIS HELPS YOU! ^_^</span>
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Using the inverse function, it is found that the equation is:

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---------------------------

We want to find the inverse of:

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To do this, we <u>exchange y and t, and isolate y.</u>

Then:

10\ln{50y - 1000} = t

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e^{\ln{50y - 1000}} = e^{0.1t}

50y - 1000 = e^{0.1t}

50y = e^{0.1t} + 1000

y = \frac{e^{0.1t} + 1000}{50}

y = \frac{e^{0.1t}}{50} + \frac{1000}{50}

P(t) = \frac{e^{0.1t}}{50} + 20

It's initial value is:

P(0) = \frac{e^{0.1(0)}}{50} + 20 = 0.02 + 20 = 20.02

Rounding, 20.

A similar problem is given at brainly.com/question/23950969

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