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sdas [7]
2 years ago
7

What is the correct solution to the expressions 3 + 5^2

Mathematics
2 answers:
Sidana [21]2 years ago
6 0

Answer:

28

Step-by-step explanation:

3+5^2

3+25

28

kobusy [5.1K]2 years ago
3 0

Answer:

28

Step-by-step explanation:

5^2=5*5

5*5=25

25+3=28

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John writes a number sequence starting with 8. Write the next number 8, 22, 36, _______
BlackZzzverrR [31]

Answer:

50

Step-by-step explanation:

from the question that we have been given, we have to find out the next number after 36.

John's next number sequence will be 50. Every number after 8 can be gotten by adding 14. So when we add 14 to 36, we get the final answer, which is the next number in the sequence.

This can be seen below:

14 + 8 = 22

14 +22 =36

14 +36 =50

therefore the next sequence would be 50

6 0
2 years ago
When x pounds of force is applied to one end of a lever that is L feet long, the resulting force y on the other end is
nadezda [96]
The question is worded poorly, but it looks like you have a lever in equilibrium, with a force x at a distance d from the fulcrum, and a force y at a distance L - d from the fulcrum. You already have the equilibrium formula for this situation:

xd = y(L - d)

If you know x, y, and d, you can solve for the length L.
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2 years ago
Triangle ABC is equilateral. What is the measure of angle B?
Sonbull [250]

Answer:

60

Step-by-step explanation:

Equilateral triangles- all 3 angles are 60

5 0
3 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
Pedro grew 4 1/3 inches during a 3 ½ month growth spurt. If his growth spurt continued at the same rate how much did he grow in
borishaifa [10]

4 1/3 divided by 3 1/2.  = 1.23

6 0
3 years ago
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