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Serjik [45]
3 years ago
12

How can the average rate of change be found using a discrete graph?

Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0
In general, the average rate of change of f (x) on the interval a, b is given by f(b) – f(a) / b – a. The average rate of alteration of a function, f (x) on an interval is well-defined to be the variance of the function values at the endpoints of the interim divided by the difference in the x values at the endpoints of the interval. this is also known as the difference quotient that tells how on average, the y values of a function are changing in connection to variations in the x values. A positive or negative rate of change is applicable which match up to an increase or decrease in the y value among the two data points. It is called zero rate of change when a quantity does not change over time.
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A sample in which every person object or event has a equal chance of being selected
NemiM [27]

Answer:

Random Sample

Step-by-step explanation:

5 0
3 years ago
. An urn contains 6 blue and 5 red marbles. Reach in and grab one marble and then another (without replacing the first one). Wha
natima [27]

Probability that you have chosen 2 red marbles is 3/11

<h2>How to solve?</h2>

Total number of marbles = 6 + 5 = 11

Number of red marbles = 6

Number of blue marbles = 5

Important Points:

1. Replacement is not allowed

2. Blue is followed by Red

Probability has been introduced in Maths to predict how likely events are to happen. The meaning of probability is basically the extent to which something is likely to happen.

Probability of Blue first = 5/11

Probability of Red second = 6/10 (one marble is already taken out)

Probability = 5/11 * 6/10 = 3/11

Learn more about Probability:

brainly.com/question/4313883

#SPJ4

8 0
2 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
NO LINKS!!!<br><br>Find the indicated side for each triangle below:​
pogonyaev

Problem 5

Apply the Law of Sines

s/sin(S) = r/sin(R)

s/sin(78) = 10/sin(48)

s = sin(78)*10/sin(48)

s = 13.162274

<h3>Answer:    13.162274 approximately</h3>

=============================================================

Problem 6

Use the Law of Sines here as well.

x/sin(X) = y/sin(Y)

x/sin(53) = 6/sin(22)

x = sin(53)*6/sin(22)

x = 12.791588

<h3>Answer:    12.791588 approximately</h3>
8 0
2 years ago
Read 2 more answers
A) Find a recurrence relation for the number of bit strings of length n that contain a pair of consecutive 0s.
Fed [463]

Answer:

A) a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

B) a_{0} = a_{1} = 0

C)   for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

Step-by-step explanation:

A) A recurrence relation for the number of bit strings of length n that contain a  pair of consecutive Os can be represented below

if a string (n ) ends with 00 for n-2 positions there are a pair of  consecutive Os therefore there will be : 2^{n-2} strings

therefore for n ≥ 2

The recurrence relation for the number of bit strings of length 'n' that contains consecutive Os

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

b ) The initial conditions

The initial conditions are : a_{0} = a_{1} = 0

C) The number of bit strings of length seven containing two consecutive 0s

here we apply the re occurrence relation and the initial conditions

a_{n} = a_{n-1} + a_{n-2} + 2^{n-2}

for n = 2

  a_{2} = 1

for n = 3

 a_{3} = 3

for n = 4

a_{4} = 8

for n = 5

a_{5} = 19

7 0
3 years ago
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