Step-by-step explanation:
g of load= 30 kg ( kilogram)
load at top of building=20 kg( kilogram)
building height=13 m(meter)
<h2>or"= total work done=?</h2>
<h3> or"=. power developed by him= ? </h3>
now ,
30*20*13÷20
again ,30*20*13
________
20
answer,= 390
To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.
h = -16t^2 + 56t
h = -16t^2 + 156t - 248
-16t^2 + 56t = -16t^2 + 156t - 248
You can cancel out the -16t^2's to get
56t = 156t - 248
=> 0 = 100t - 248
=> 248 = 100t
=> 2.48 = t
Using this time value, plug into either equation to find the height.
h = 16(2.48)^2 + 56(2.48)
Final answer:
h = 40.4736
Hope I helped :)
