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taurus [48]
4 years ago
11

Simplify: 2(4x - 6) - 8 + 10x

Mathematics
2 answers:
Snezhnost [94]4 years ago
7 0
18x-20 is the answer
Darya [45]4 years ago
6 0

Answer:

Hi there!

The simplified version is:

18x-20

Step-by-step explanation:

2(4x-6) -8 +10x

First, multiply the 2 by the parentheses.

8x -12 -8 +10x

Next, combine like terms

18x -20

This is the simplified version!

Hope this helps

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Lorico [155]

3a / b²

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4 0
3 years ago
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What is the area of this polygon? 28.5 units² 34.5 units² 37.5 units² 40.5 units² 6 sided polygon on a coordinate plane with ver
LUCKY_DIMON [66]

Answer:

Option B.

Step-by-step explanation:

The given vertices of the polygon are (-6,-2),(-5,1),(-1,4),(1,1),(5,3),(1,-2).

We need to find the area of the polygon.

Plot the given vertices and on a coordinate plane and draw the polygon. Divide the polygon in 4 parts as shown below.

Area of rectangle is

A=length\times width

Area of triangle is

A=\dfrac{1}{2}\times base\times height

Area of each figure is

A_1=\dfrac{1}{2}\times 1\times 3=1.5

A_2=\dfrac{1}{2}\times 6\times 3=9

A_3=\dfrac{1}{2}\times 4\times 3=6

A_4=6\times 3=18

Area of polygon is

A=A_1+A_2+A_3+A_4

A=1.5+9+6+18=34.5

The area of polygon is 34.5 units².

Therefore, the correct option is B.

3 0
4 years ago
A movie theater sells popcorn in bags that open to form similar prisms, as shown. The large bag has a volume of 576 cubic inches
liq [111]

Answer:

Can't be determined

Explanation:It can't be determined since there are two sides that you need to find out.

8 0
4 years ago
Help im in class and i need this question done nowww -1.8 ÷ 0.2
monitta
The answer would be -9
6 0
3 years ago
What are the values of x and y?
adoni [48]

Answer:

Step-by-step explanation:

hello :

use pytagor-rule :

triangle ABC : (x+15)² =17²+y²....(*)

triangle BDC : y² = x²+8²....(**)

by (**) put the value of y² in (*) :

(x+15)² = 17²+x²+8²

x²+30x+15² = 17²+x²+18²

30x +225 = 289+64

30x = 128

x= 128/30

x= 64/15

put this value in (**) calculate y²  ......continu

4 0
4 years ago
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