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Rina8888 [55]
3 years ago
9

A line passes through point (-2,5) and has a slope of 2/3. Points A (x,3) and B (-2,y) lie on on the line.

Mathematics
1 answer:
kolezko [41]3 years ago
3 0
Have you attempted to graph the line

Remember *rise / run*
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PLEASE HELP ASAP WILL GIVE BRAINLIEST!!!!
max2010maxim [7]

Answer:

Step-by-step explanation:

y intercept is -6

the slope is already in it's fraction form but if you want it back to whole number it's y=1.33x-6

the slope is positive

Some plots you can put are (6, 2) and (12, 10)

Just start at (0, -6) and counts 4 up and 3 right

4 0
3 years ago
1. What is the actual distance around the garden? Explain your reasoning.
Mrrafil [7]
First find the number of ft around the garden and if it took Clare 30 min to walk the entire distance divide your previous answer by 30 so you can see how many ft per minute she was walking
5 0
3 years ago
Please help Need help
Anettt [7]
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where 
m=slope of line
(x0,y0) is a point through which the line passes.

We know that the line passes through A(3,-6), B(1,2)

All options have a slope of -4, so that should not be a problem.  In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.

So we can check which line passes through which point:

a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3)  means that line passes through A(3,-6) => ok

b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
   ****** this equation is not the line passing through A & B *****

c. y=-4x+6  subtract 2 from both sides (to make the y-coordinate 2)
   y-2 = -4x+4, rearrange
   y-2 = -4(x-1)  
   which means that it passes through B(1,2), so ok

d. y-2=-4(x-1)
   this is the same as the previous equation, so it passes through B(1,2), 
   this equation is ok.

Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
   
8 0
3 years ago
In ΔOPQ, the measure of ∠Q=90°, OQ = 80, QP = 39, and PO = 89. What ratio represents the cosecant of ∠P?
Serjik [45]

Answer:

cos(O) = 39 / 89

Step-by-step explanation:

Given:

ΔOPQ, where

∠Q=90°

PO = 89

OQ = 39

QP = 80

cosine of ∠O?

cos(O) = Adjacent / Hypotenuse

cos(O) = 39 / 89

3 0
3 years ago
Read 2 more answers
to support a tree damaged in a storm, a 12-foot wire is secured from the ground to the tree at a point 10 feet off the ground. t
Leokris [45]
Choice given:
<span>33.6°
39.8°
50.2°
56.4°

I drew the figure. 
I got 12 ft as the hypotenuse, 10 ft as the opposite.

Sin</span>Θ = opposite / hypotenuse 
SinΘ = 10/12
SinΘ = 0.83

I used the calculator to get the value of each angle using the sine function
sin(33.6°) = 0.55
sin(39.8°) = 0.64
sin(50.2°) = 0.77
sin(56.4°) = 0.83

The angle where the wire meets the ground is approximately 56.4°
8 0
4 years ago
Read 2 more answers
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