Answer:
Step-by-step explanation:
y intercept is -6
the slope is already in it's fraction form but if you want it back to whole number it's y=1.33x-6
the slope is positive
Some plots you can put are (6, 2) and (12, 10)
Just start at (0, -6) and counts 4 up and 3 right
First find the number of ft around the garden and if it took Clare 30 min to walk the entire distance divide your previous answer by 30 so you can see how many ft per minute she was walking
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Answer:
cos(O) = 39 / 89
Step-by-step explanation:
Given:
ΔOPQ, where
∠Q=90°
PO = 89
OQ = 39
QP = 80
cosine of ∠O?
cos(O) = Adjacent / Hypotenuse
cos(O) = 39 / 89
Choice given:
<span>33.6°
39.8°
50.2°
56.4°
I drew the figure.
I got 12 ft as the hypotenuse, 10 ft as the opposite.
Sin</span>Θ = opposite / hypotenuse
SinΘ = 10/12
SinΘ = 0.83
I used the calculator to get the value of each angle using the sine function
sin(33.6°) = 0.55
sin(39.8°) = 0.64
sin(50.2°) = 0.77
sin(56.4°) = 0.83
The angle where the wire meets the ground is approximately 56.4°