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Nuetrik [128]
4 years ago
11

Based on historical data, an insurance company estimates that a particular customer has a 2.4% likelihood of having an accident

in the next year, with the average insurance payout being $2700.
If the company charges this customer an annual premium of $250, what is the company's expected value of this insurance policy?
Mathematics
1 answer:
solong [7]4 years ago
8 0

Answer:

The expected value of this insurance policy is kept at $185.2 based on the historical data provided

Step-by-step explanation:

probability/likelihood of having an accident by the customer is = 2.4% which is 2.4÷100 = 0.024 probability :

The cost to the company at 0.024 probability of having an accident

=  - $2700 (average insurance payout)

probability of not having an accident by the customer is =  100% - 2.4%  = 97.6% which is 97.6 ÷ 100 = 0.976 probability

The cost to the company at 0.976 probability of no accident = $0

The premium paid by the customer annually is = $250

Therefore to get the expected value of the insurance policy (E) will be

(probability of accident) (average insurance payout) + (probability of no accident) (cost of no accident to the company) + premium paid by customer  

0.024(-$2700) + 0.976($0) + $250 = $185.2

- $64.8 + $0 + $250 = $185.2

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1)  The answer, in terms of  "π", is:
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  "  (\frac{1372 mm^3}{3}) *  π    mm³ " .
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2) The answer, using "3.14" for "π", is:
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" 1436.0266666666666667  mm³ " ; round to: " 1436.027 mm³ " ; 

        or; write as: " 1436 \frac{2}{75}  mm³ " .
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Explanation: 
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The formula for the volume, "V" of a sphere is:

V = \frac{4}{3} * π* r³ ;

in which "r" = radius = "7 mm" {given}.

We can solve using "3.14" for "π" ; or we can solve in terms of "π" ;
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1)  In terms of "π" :
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   V = \frac{4}{3} * π * r³ ;

      = \frac{4}{3} * π * (7 mm)³ ;

      = \frac{4}{3} * π * (7 * 7 * 7 * mm³) ;
 
      = \frac{4}{3} * π * (49 * 7 * mm³) ;

      = \frac{4}{3} * π * (343 mm³) ;

      = \frac{4* 343 mm^3}{3}) * π   mm³

      =  (\frac{1372 mm^3}{3}) *  π    mm³  ;

________________________________________________________
2)  Using "3.14" for "π" :
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     V = \frac{4}{3} * π * r³ ; 

        = \frac{4}{3} * (3.14)* (7 mm)³ ;

        = \frac{4}{3} * (3.14) * (7 * 7 * 7 * mm³) ;

        = \frac{4}{3} * (3.14) * (49 * 7 * mm³) ;

        = \frac{4}{3} * (3.14) * (49 * 7 * mm³) ;

        = \frac{4}{3} * (3.14)  * (343 mm³) ;

        = { \frac{4}{3} }  * (3.14 * 343 mm³) ;

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__________________________________________________________
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        or; write as: " 1436 \frac{2}{75}  mm³ " .
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