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Akimi4 [234]
3 years ago
14

Work out the following questions ​

Mathematics
1 answer:
Basile [38]3 years ago
6 0

Answer: The first one is 2 2/3 and the second one is 10 1/2

Step-by-step explanation: So 2/3 divided by 1/4. First you would do keep, change, flip. Then that would give you 2/3 times 4/1. 2/3 times 4/1 would be 8/3 which can be simplified to 2 2/3. The second one 7 divided by 2/3. Again do keep, change, flip. 7 times 3/2. This would give you 21/2 when you simplify you get 10 1/2.

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This year, jake is 5 years older than his sister. Three years ago, jake was twice his sisters age. How old is jakes sister now?
ruslelena [56]

you don't have enough info, we need to know how old he was when he was twice her age, or how old she was

6 0
3 years ago
Identify the center and the radius of each.<br><br> x^+y^+26x-22y+281=0
inessss [21]

Answer:

Center (-13,11) , radius 3

Step-by-step explanation:

The given circle has equation

x^2+y^2+26x-22y+281=0

We compare this to the general equation.

x^2+y^2+2ax+2by+c=0

where (-a,-b) is the center.

This implies that;

2a=26

\Rightarrow a=13

2b=-22

b=-11

The center is therefore (-13,11)

The radius is given by

r=\sqrt{a^2+b^2-c}

r=\sqrt{13^2+(-11)^2-281}

r=\sqrt{9}

The radius is 3

3 0
3 years ago
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
4 years ago
25/7 as a mixed number
Aleks [24]
3 and four sevenths bcs 25divided by seven is 3r4
7 0
3 years ago
Read 2 more answers
Sean, a freelance editor, charges the rates shown in the table below to edit manuscripts. The cost per page increases as the qua
Gnom [1K]
85c - 0.5(85c) = 161.5
85c - 4.25c = 161.5
80.75c = 161.5
c = 161.5 / 80.75
c = 2............so she needs express proofreading
==================
x - 3 < -7                  x + 5 > = 8
x < -7 + 3                 x > = 8 - 5
x < -4                       x > = 3

open circle on -4, shading to the left....closed circle on 3, shading to the right

7 0
3 years ago
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