Brian rolls 2 fair dice and adds the results from each. Work out the probability of getting a total that is more than 1.

Mathematics

1 answer:

9966 [12]3 years ago

8 0

Answer:

To determine the probability of rolling any one of the numbers on the die, we divide the event frequency (1) by the size of the sample space (6), resulting in a probability of 1/6. Rolling two fair dice more than doubles the difficulty of calculating probabilities.

Step-by-step explanation:

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Answer:

$\large\boxed{\sqrt[3]{\left(\dfrac{15}{4}\right)^2}}$

Step-by-step explanation:

$a^\frac{n}{m}=\sqrt[m]{a^n}\\---------------------\\\\\left(5\times\dfrac{3}{4}\right)^\frac{2}{3}=\left(\dfrac{5\times3}{4}\right)^\frac{2}{3}=\left(\dfrac{15}{4}\right)^\frac{2}{3}=\sqrt[3]{\left(\dfrac{15}{4}\right)^2}$

Answer:

$\large\boxed{C.\ \sqrt5}$

Step-by-step explanation:

$\left(5^\frac{3}{4}\right)^\frac{2}{3}\\\\\text{Use}\ (a^n)^m=a^{nm}\\\\5^{\frac{3}{4}\cdot\frac{2}{3}}=5^{\frac{1}{2}\cdot\frac{1}{1}}=5^\frac{1}{2}=\sqrt[2]5=\sqrt5$