Part 1: 2×2×3×3×3=108 (c)
Part 2: 10×9×26×25×4=234000 (c)
Part 3: 10×9×8×7×6×5×4×3×2×1÷(3×2×1)=604800 (d)
Part 4: 11C4=11×10×9×8÷(4×3×2×1)=330 (a)
Part 5: ⅕=20% (c)
Part 6: 100-2.9=97.1 (d)
9×8-29+30/15-15 equals 30
Answer:
Required largest volume is 0.407114 unit.
Step-by-step explanation:
Given surface area of a right circular cone of radious r and height h is,
and volume,
To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,
subject to,
We know for maximum volume . So let be the Lagranges multipliers be such that,
And,
Substitute (3) in (2) we get,
Substitute this value in (1) we get,
Then,
Hence largest volume,