Answer:
f(2)=0. The third option is correct.
Step-by-step explanation:
Suppose we have a polynomial called f(x) and we know (x-2) is a factor of f. This means that we can express f(x) as:
f(x)=(x-2)\cdot g(x)
Being g(x) another unknown function.
Option 1: f(0)=(0-2)\cdot g(0)=-2\cdot g(0). Since we don't know the value of g(0), we cannot assure f(0)=-2. Incorrect
Option 2: f(-2)=(-2-2)\cdot g(-2)=-4\cdot g(-2). Since we don't know the value of g(-2), we cannot assure f(-2)=0. Incorrect
Option 3: f(2)=(2-2)\cdot g(2)=0\cdot g(0)=0. Regardless of the value of g(0), f(0) must be 0. Correct
Option 4: f(0)=(0-2)\cdot g(0)=-2\cdot g(0). Since we don't know the value of g(0), we cannot assure f(0)=2. Incorrect
<h2>
Answer with explanation:</h2>
Given : The number of children a family plans to have = 7
If the boys and girls are equally likely, then the probability of getting a girl = probability of getting boy =
Now, the probability that there will be at least one girl will be:-
P(atleast one girl) = 1- P(all boys)
Hence, the probability that there will be at least one girl = 0.9921875
Since ,0.9921875 > 0.5
It means the event is likely to happen. [∵Any event E is likely to happen if P(E)>0.5]
Therefore, the probability is high enough for the couple to be very confident that they will get at least one girl in 7 children.
....do you own a calculator? The computer or phone you're posting this question on should have one.