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Misha Larkins [42]
3 years ago
5

Of the three lines in the graph ,one has slope 1 ,one has slope 2, and one has slope 1/5

Mathematics
1 answer:
snow_lady [41]3 years ago
5 0
Each time the line makes a “stop” at an intersection of graph lines, make a point. Count how many it takes to go up and across from one point to another. Think of it as a fraction: top number is how many it takes to go up, bottom number is how many it takes to go across. If top number is going up, then it is positive. If it is going down, it is a negative number. So the answer is STEEPEST slope is 2, LEAST steep is 1/5, and the MIDDLE one is 1.
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Find f(-2) when f(t) = -2t + 3<br><br> A) -7 <br> B) -1 <br> C) 1 <br> D) 7
Lady bird [3.3K]

Answer: -1

Step-by-step explanation:

f(t) =  -2t + 3

f(-2) = -2 x -2 + 3                [ substituting the value]

f(-2) = -4 + 3

f(-2) = -1

5 0
3 years ago
Descried how to derive the quadratic formula from a quadratic equation in standard form
Aleks [24]

Answer:

The standard form of a quadratic equation is:

ax^2+bx+c=0, a\neq 0

Quadratic Formula Derivation:

ax^2+bx+c=0\\

$x^2+\frac{b}{a}x+\frac{c}{a} =0 $

$x^2+\frac{b}{a}x = -\frac{c}{a}$

Completing the Square:

$x^2+\frac{b}{a}x +\frac{b^2}{4a^2} = \frac{b^2}{4a^2}-\frac{c}{a}$

$  ( x+\frac{b}{2a} )^2 =  \frac{b^2-4ac}{4a^2}  $

Square Root property:

$x+\frac{b}{2a}  = \pm \sqrt{ \frac{b^2-4ac}{4a^2}}   $

$x  = -\frac{b}{2a} \pm  { \frac{\sqrt {b^2-4ac}}{2a}}   $

$x  =  \frac{-b\pm\sqrt{b^2-4ac}} {2a}  }   $

8 0
3 years ago
Some one help me !!!!
Sladkaya [172]

Answer: I cant see image!!!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Answers for both boxes please ​
Neporo4naja [7]

Answer:

i think its -1

Step-by-step explanation:

sorry if im wrong

3 0
3 years ago
It was reported that in​ 2004, the mean net worth of families in a certain region was ​$470.2 thousand and the median net worth
Kobotan [32]

Answer:

Median.

Step-by-step explanation:

We have been given that in​ 2004, the mean net worth of families in a certain region was ​$470.2 thousand and the median net worth was ​$92.3 thousand.

We know that mean and median of a symmetric data set is equal.

We also know that when mean of a data set is greater than median, then the data set has a very large valued outlier.

Since mean net wroth of families is approximately 5 times more than median net wroth of families, this means that some of the families has very high net worth as outliers.

Since the net worth of families has very large outliers, therefore, I would prefer median as the appropriate measure of center as median is not affected by outliers.

6 0
4 years ago
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