Question

find the length of a rectangular lot with a perimeter of 54 meters if the length is 13 meters more than the width

Answer 1

Perimeter of a rectangle is 2 times the sum of the length and width

p=2(l+w)  and we are told that p=54 and l=13+w so

54=2(13+w+w)  divide both sides by 2

27=13+2w  subtract 13 from both sides

14=2w  divide both sides by 2

w=7, and since l=w+13

l=20

So the length of the lot is 20 meters.