Find the equation of a line perpendicular to 4x+2y=3 that contains the point (1,5)
1 answer:
Answer:
x -2y = -9
Step-by-step explanation:
We can start by swapping the coefficients of x and y, then negating one of them. We can finish by evaluating the expression at the given point to find the constant.
2x -4y = constant
2(1) -4(5) = -18 = constant
So, an equation could be ...
2x -4y = -18
We notice that all of the coefficients of this equation are divisible by 2, so we can remove a factor of 2 from the equation:
x -2y = -9
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