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3 years ago

9

Plz Help!!! And plz explain how you got the answer. Will give brainiest

1 answer:

Aleks [24]3 years ago

4 0

D is the answer and here’s why

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How do I set this up

Galina-37 [17]

Answer:

Jaheem has a goal running a total of 125 miles this month. Each day that he ran, he ran 7 miles. Which expression could Jaheem use to determine how many miles he has left to run after running for d days?

x a.

125 – 7d

x b.

7d + 125

x c. fraction numerator 125 over denominator 7 d end fraction

x d.

7dStep-by-step explanation:Jaheem has a goal running a total of 125 miles this month. Each day that he ran, he ran 7 miles. Which expression could Jaheem use to determine how many miles he has left to run after running for d days?

x a.

125 – 7d

x b.

7d + 125

x c. fraction numerator 125 over denominator 7 d end fraction

x d.

7d

5 0

3 years ago

What is 7,045 divided by 15

disa [49]

Answer:

469.6

Step-by-step explanation:

7045/15

7 0

3 years ago

t is your sister's birthday and you are preparing a family meal. The joint of meat needs to be cooked for 30 minutes per 500 g p

emmainna [20.7K]

1 kg = 1000 g....so 2.5 kg = (2.5 * 1000) = 2500 grams

it cooks 30 minutes per 500 g.....2500/500 = 5...so there are 5 thirty minute periods ....(5 * 30) = 150 minutes....plus the extra 20 minutes....(150 + 20) = 170 minutes....so your answerr is 2 hrs 50 minutes

4 0

3 years ago

Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

$30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)$

$48x+20=15-6x$ ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$48x+6x=15-20$

$54x=-5$ ---------> equation C

Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

<u>Case a)</u> $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

so

the case a) have the same solution that the given equation

<u>Case b)</u> $18x+20+30x=15-6x$

Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

so

the case b) have the same solution that the given equation

<u>Case c)</u> $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

$19x+6x=15-20\\25x=-5\\x=-0.20$

$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

<u>Case d)</u> $24x+30x=-5$

Combine like terms in left side

$54x=-5$

the case d) is equal to the equation C

so

the case d) have the same solution that the given equation

<u>Case e)</u> $12x+30x=-5$

Combine like terms in left side

$42x=-5$

$x=-5/42=-0.12$

$-0.12\neq -0.09$

therefore

the case e) not have the same solution that the given equation

therefore

<u>the answer is</u>

case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

7 0

4 years ago

Read 2 more answers

Factorise x^3+3x^2y+3xy^2+y^3

Nesterboy [21]

Answer:

<em>(x + y)³</em>

Step-by-step explanation:

<em> use (a + b)³ = a³ + 3a²b + 3ab² + b³</em>

<em>x³ + 3x²y + 3xy² + y³ =</em>

<em>= (x + y)³</em>

7 0

3 years ago